Explanation Given that the velocity of the sailboat is 6.28 m / s , acceleration of the sailboat is 0.714 m / s 2 , and the wind gust last for 5.42 s . Write the expression for acceleration of the sailboat in the horizontal direction. a x = a cos θ (I) Here, a x is the acceleration of the sailboat in the horizontal direction, a is the magnitude of acceleration, θ is the angle sailboat makes with the original direction. Write the expression for acceleration of the sailboat in the vertical direction. a y = a sin θ (II) Here, a y is the acceleration of the sailboat in the vertical direction, a is the magnitude of acceleration, θ is the angle sailboat makes with the original direction. Write the expression for displacement along x direction. Δ x = v 0 t + 1 2 a x t 2 (III) Here, Δ x is the displacement along x direction, t is the time, and v 0 is the initial velocity of the sailboat along x direction. Write the expression for displacement along y direction. Δ y = 1 2 a y t 2 (IV) Here, Δ y is the displacement along y direction. Write the expression for magnitude of the displacement vector. Δ r = ( Δ x ) 2 + ( Δ y ) 2 (V) Here, Δ r is the magnitude of the displacement vector. Conclusion: Substitute 0.714 m / s 2 for a , and 48.8 ° for θ in equation (I), to find a x . a x = ( 0.714 m / s 2 ) cos ( 48.8 ° ) = 0.470 m / s 2 Substitute 0.714 m / s 2 for a , and 48

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ISBN: 9780136780984

Author: Wolfson

Publisher: PEARSON

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Chapter 3, Problem 44E

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The magnitude of the board’s displacement.

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Chapter 3, Problem 43E

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