Chapter 3, Problem 3.1P

To determine

To write:

A script that will calculate the circumference of a circle $\left(\text{C}=2\text{πr}\right)$.

Answer to Problem 3.1P

Solution:

The created variable $\text{C}$ is “C = 79.587”.

Explanation of Solution

The formula to calculate the circumference of a circle is,

$\text{C}=2\text{πr}$

Here, the radius of the circle is $\text{r}$.

Consider, the radius is $\text{r}=2$.

Substitute $2$ for $\text{r}$ in the above formula.

$\begin{array}{rll}\text{C}& =& 2\text{π}\left(2\right)\\ & =& 4\text{π}\\ & =& 12.5664\end{array}$

MATLAB Code:

clc

clear all

close all

r = 2;

% Define the variable r.

C = (2*pi*r)

% Define the variable circumference.

Save the MATLAB script with name, chapter3_54793_3_1P.m in the current folder. Execute the script by typing the script name at the command window to create a variable C and store circumference in it, define the variable $\text{r}$ and define the variable $\text{C}$.

Result:

Therefore, the created variable $\text{C}$ is “C = 12.5664”.