ENGINEERING YOUR FUTURE
9th Edition
ISBN: 9780190279288
Author: Oakes
Publisher: OXF
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Chapter 3, Problem 3.1EAA
To determine
The number of first-year, full-time enrollments expected in 2010 if the administrator used the data from 1975 to 1980 and to calculate the percentage error.
Expert Solution & Answer
Answer to Problem 3.1EAA
The number of first-year full time enrollments expected in 2010 if the administrator used the data from 1975 to 1980 as 375000 students and the percentage error is 226%.
Explanation of Solution
Given information:
As per the given data, to find the error percentage upon usage of the data from 1975 to 1980 to predict the number of first-year full time enrollments expected in 2010.
According to the data in the Engineering for your future book, the following table illustrates the actual data for the years 1975 to 2010 and the predicted data for the year 2010 using only the estimates from 1975 to 1980.
| Year | Actual enrollments | Predicted enrollments |
| 1975 | 45000 | 45000 |
| 1980 | 118000 | 118000 |
| 1985 | 115000 | 143000 |
| 1990 | 90000 | 200000 |
| 1995 | 80000 | 237000 |
| 2000 | 82000 | 287000 |
| 2005 | 110000 | 328000 |
| 2010 | 115000 | 375000 |
The following is a graphical illustration of the same data in the table:
The above graph shows huge differences in the predicted data since it has taken the data belonging to the years 1975 to 1980 and prorated the same to the rest of the years until 2010. By doing this, the administrator has missed few important factors like the number of births every year; number of high school graduates every year, and other economic factors. These factors tend to change year after year and by taking only the data from 1975 to 1980, the number of enrollments for several years cannot be predicted accurately.
The percentage of error can be calculated as:
Percentage error
This shows that there is a huge percentage error upon the usage of the data from 1975 to 1980 to predict the number of first-year full time enrollments expected in 2010.
Conclusion:
Thus, the number of first year full-time enrollments expected in 2010 if the administrator used the data from 1975 to 1980 and the percentage error is discussed in details.
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Problem 6 (Optional, extra 6 points)
150 mm
150 mm
120 mm
80 mm
60 mm
PROBLEM 18.103
A 2.5 kg homogeneous disk of radius 80 mm rotates with an
angular velocity ₁ with respect to arm ABC, which is welded
to a shaft DCE rotating as shown at the constant rate
w212 rad/s. Friction in the bearing at A causes ₁ to
decrease at the rate of 15 rad/s². Determine the dynamic
reactions at D and E at a time when ₁ has decreased to
50 rad/s.
Answer:
5=-22.01 +26.8} N
E=-21.2-5.20Ĵ N
Problem 1.
Two uniform rods AB and CE, each of weight 3 lb and length 2 ft, are welded to each other at their
midpoints. Knowing that this assembly has an angular velocity of constant magnitude c = 12 rad/s,
determine:
(1). the magnitude and direction of the angular momentum HD of the assembly about D.
(2). the dynamic reactions (ignore mg) at the bearings at A and B.
9 in.
3 in.
03
9 in.
3 in.
Answers: HD = 0.162 i +0.184 j slug-ft²/s
HG = 2.21 k
Ay =-1.1 lb; Az = 0; By = 1.1 lb; B₂ = 0.
Problem 5 (Optional, extra 6 points)
A 6-lb homogeneous disk of radius 3 in. spins as shown at the constant rate w₁ = 60 rad/s. The disk
is supported by the fork-ended rod AB, which is welded to the vertical shaft CBD. The system is
at rest when a couple Mo= (0.25ft-lb)j is applied to the shaft for 2 s and then removed. Determine
the dynamic reactions at C and D before and after the couple has been removed at 2 s.
4 in.
C
B
Mo
5 in
4 in.
Note: 2 rotating around CD induced by Mo is NOT
constant before Mo is removed.
and ₂ (two
unknowns) are related by the equation: ₂ =0+ w₂t
3 in.
Partial Answer (after Mo has been removed):
C-7.81+7.43k lb
D -7.81 7.43 lb
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