General, Organic, and Biochemistry
9th Edition
ISBN: 9780078021541
Author: Katherine J Denniston, Joseph J Topping, Dr Danae Quirk Dorr
Publisher: McGraw-Hill Education
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Chapter 3, Problem 3.13QP
(a)
Interpretation Introduction
Interpretation:
The Lewis symbol of
(a)
Expert Solution
Explanation of Solution
The given compound is hydrogen. It has one valence electron.
The Lewis symbol of hydrogen is:
(b)
Interpretation Introduction
Interpretation:
The Lewis symbol of
(b)
Expert Solution
Explanation of Solution
The given compound is helium. It has two valence electrons.
The Lewis symbol of helium is:
(c)
Interpretation Introduction
Interpretation:
The Lewis symbol of
(c)
Expert Solution
Explanation of Solution
The given compound is silicon. Silicon is present in group VI. It has six valence electrons.
The Lewis symbol of silicon is:
(d)
Interpretation Introduction
Interpretation:
The Lewis symbol of
(d)
Expert Solution
Explanation of Solution
The given compound is nitrogen. Nitrogen is present in group V. It has five valence electrons.
The Lewis symbol of nitrogen is:
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Students have asked these similar questions
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
R lactam or lactone considering as weak acid or weak base and why
Chapter 3 Solutions
General, Organic, and Biochemistry
Ch. 3.1 - Draw the Lewis symbol for oxygen, and indicate the...Ch. 3.1 - Prob. 3.2PPCh. 3.1 - Prob. 3.3PPCh. 3.2 - Prob. 3.4PPCh. 3.2 - Prob. 3.5PPCh. 3.2 - Prob. 3.1QCh. 3.2 - Prob. 3.2QCh. 3.2 - Prob. 3.6PPCh. 3.2 - Prob. 3.7PPCh. 3.2 - Prob. 3.8PP
Ch. 3.2 - Prob. 3.9PPCh. 3.4 - Prob. 3.10PPCh. 3.4 - Prob. 3.11PPCh. 3.4 - Prob. 3.12PPCh. 3.4 - Prob. 3.13PPCh. 3.4 - Prob. 3.3QCh. 3.4 - Prob. 3.4QCh. 3.4 - Prob. 3.14PPCh. 3.4 - Prob. 3.5QCh. 3.4 - Prob. 3.6QCh. 3.4 - Prob. 3.16PPCh. 3.4 - Prob. 3.7QCh. 3.4 - Prob. 3.8QCh. 3.4 - Prob. 3.9QCh. 3 - Prob. 3.13QPCh. 3 - Draw the appropriate Lewis symbol for each of the...Ch. 3 - Draw the appropriate Lewis symbol for each of the...Ch. 3 - Prob. 3.16QPCh. 3 - Describe the differences between covalent bonding...Ch. 3 - Describe the difference between nonpolar covalent...Ch. 3 - What is the periodic trend of electronegativity?
Ch. 3 - What role does electronegativity play in...Ch. 3 - Use electronegativity values to classify the bonds...Ch. 3 - Use electronegativity values to classify the bonds...Ch. 3 - When there is a reaction between each of these...Ch. 3 - Prob. 3.24QPCh. 3 - Explain, using Lewis symbols and the octet rule,...Ch. 3 - Explain, using Lewis symbols and the octet rule,...Ch. 3 - Prob. 3.27QPCh. 3 - Prob. 3.28QPCh. 3 - Name each of the following ions:
Na+
Cu+
Mg2+
Ch. 3 - Name each of the following ions:
Cu2+
Fe2+
Fe3+
Ch. 3 - Name each of the following ions:
HCO3–
H3O+
CO32−
Ch. 3 - Prob. 3.32QPCh. 3 - Prob. 3.33QPCh. 3 - Write the formula for each of the following...Ch. 3 - Prob. 3.35QPCh. 3 - Prob. 3.36QPCh. 3 - Prob. 3.37QPCh. 3 - Predict the formula of a compound formed...Ch. 3 - Prob. 3.39QPCh. 3 - Prob. 3.40QPCh. 3 - Prob. 3.41QPCh. 3 - Write the correct formula for each of the...Ch. 3 - Prob. 3.43QPCh. 3 - Write the correct formula for each of the...Ch. 3 - Prob. 3.45QPCh. 3 - Write the correct formula for each of the...Ch. 3 - Write a suitable formula for:
sodium...Ch. 3 - Write a suitable formula for:
aluminum...Ch. 3 - Prob. 3.49QPCh. 3 - Prob. 3.50QPCh. 3 - Prob. 3.51QPCh. 3 - Prob. 3.52QPCh. 3 - Write a suitable formula for:
silicon...Ch. 3 - Prob. 3.54QPCh. 3 - Contrast ionic and covalent compounds with respect...Ch. 3 - Prob. 3.56QPCh. 3 - Prob. 3.57QPCh. 3 - Prob. 3.58QPCh. 3 - Prob. 3.59QPCh. 3 - Prob. 3.60QPCh. 3 - Prob. 3.61QPCh. 3 - Prob. 3.62QPCh. 3 - Prob. 3.63QPCh. 3 - Prob. 3.64QPCh. 3 - Prob. 3.65QPCh. 3 - Prob. 3.66QPCh. 3 - How is the positive charge of a polyatomic cation...Ch. 3 - Prob. 3.68QPCh. 3 - Prob. 3.69QPCh. 3 - Prob. 3.70QPCh. 3 - Prob. 3.71QPCh. 3 - Prob. 3.72QPCh. 3 - Prob. 3.73QPCh. 3 - Prob. 3.74QPCh. 3 - Prob. 3.75QPCh. 3 - Prob. 3.76QPCh. 3 - Prob. 3.77QPCh. 3 - Prob. 3.78QPCh. 3 - Prob. 3.79QPCh. 3 - Prob. 3.80QPCh. 3 - Prob. 3.81QPCh. 3 - Prob. 3.82QPCh. 3 - Prob. 3.83QPCh. 3 - Prob. 3.84QPCh. 3 - Prob. 3.85QPCh. 3 - Prob. 3.86QPCh. 3 - Prob. 3.87QPCh. 3 - Prob. 3.88QPCh. 3 - Prob. 3.89QPCh. 3 - Prob. 3.90QPCh. 3 - Prob. 3.91QPCh. 3 - Prob. 3.93QPCh. 3 - Prob. 3.94QPCh. 3 - Prob. 3.95QPCh. 3 - Prob. 3.96QPCh. 3 - Prob. 3.97QPCh. 3 - Prob. 3.98QPCh. 3 - Prob. 3.99QPCh. 3 - Prob. 3.100QPCh. 3 - Prob. 3.101QPCh. 3 - Prob. 3.102QPCh. 3 - Prob. 3.103QPCh. 3 - Prob. 3.104QPCh. 3 - Prob. 3.107QPCh. 3 - Prob. 3.108QPCh. 3 - Prob. 3.109QPCh. 3 - Prob. 3.110QPCh. 3 - Prob. 3.112QPCh. 3 - Predict differences in our global environment that...Ch. 3 - Prob. 2CPCh. 3 - Prob. 3CPCh. 3 - Prob. 4CPCh. 3 - Prob. 5CP
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