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Concept explainers
(a)
Interpretation: The values of
Concept introduction: The compound
To determine: The values of
(a)
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Answer to Problem 3.125AP
Solution
The value of
Explanation of Solution
Explanation
Given
The mass percent of uranium in
The mass percent of oxygen in
The number of moles of the given element is calculated by using the formula,
Substitute the values of mass and molar mass of uranium in the equation (1).
Substitute the values of mass and molar mass of oxygen in the equation (1).
The calculated values are divided by the smallest number of moles to determine the simplest whole number ratio of moles of each constituent,
For uranium
For oxygen
Therefore, the formula of given compound is
The charge on the uranium in
Substitute the values of charge on oxygen and molecule in the above equation.
Thus, the value of
(b)
To determine: The values of
(b)
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Answer to Problem 3.125AP
Solution
The value of
Explanation of Solution
Explanation
Given
The mass percent of uranium in
The mass percent of oxygen in
The number of moles of the given element is calculated by using the formula,
Substitute the values of mass and molar mass of uranium in the equation (1).
Substitute the values of mass and molar mass of oxygen in the equation (1).
The calculated values are divided by the smallest number of moles to determine the simplest whole number ratio of moles of each constituent,
For uranium
For oxygen
The numbers obtained are multiplied with
The charge on the uranium in
Substitute the values of charge on oxygen and molecule in the above equation.
Thus, the value of
(c)
To determine: The values of
(c)
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Answer to Problem 3.125AP
Solution
The value of
Explanation of Solution
Explanation
Given
The compound
The mass of compound
The mass of
The mass of uranium oxide in the reaction is
The reaction involving the decomposition of
The mass of water in the reaction is calculated by subtracting the mass of
The compound
The mass of nitrogen oxides and oxygen in the reaction is calculated by subtracting the mass of
Since, the nitrogen and oxygen are present in
For nitrogen
For oxygen
The mass of uranium and oxygen in
For uranium
For oxygen
The total mass of oxygen in the given compound is,
The number of moles of the given element is calculated by using the formula,
Substitute the values of mass and molar mass of uranium in the equation (1).
Substitute the values of mass and molar mass of oxygen in the equation (1).
Substitute the values of mass and molar mass of nitrogen in the equation (1).
Substitute the values of mass and molar mass of water in the equation (1).
The calculated values are divided by the smallest number of moles to determine the simplest whole number ratio of moles of each constituent,
For uranium
For oxygen
For nitrogen
For water
Therefore, the formula of given compound is
Conclusion
The value of
The value of
The value of
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Chapter 3 Solutions
Chemistry [hardcover]
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