Use the data in Figure 3.11 and Table 3.2 to calculate the energy changes ( Δ E ) for the following pairs of reactions: (a) K ( g ) + Cl ( g ) → K + ( g ) + Cl − ( g ) K ( g ) + Cl ( g ) → K − ( g ) + Cl + ( g ) (b) Na ( g ) + Cl ( g ) → Na + ( g ) + Cl − ( g ) Na ( g ) + Cl ( g ) → Na − ( g ) + Cl + ( g ) Explain why K + Cl − and Na + Cl − form in preference to K − Cl + and Na − Cl + .
Use the data in Figure 3.11 and Table 3.2 to calculate the energy changes ( Δ E ) for the following pairs of reactions: (a) K ( g ) + Cl ( g ) → K + ( g ) + Cl − ( g ) K ( g ) + Cl ( g ) → K − ( g ) + Cl + ( g ) (b) Na ( g ) + Cl ( g ) → Na + ( g ) + Cl − ( g ) Na ( g ) + Cl ( g ) → Na − ( g ) + Cl + ( g ) Explain why K + Cl − and Na + Cl − form in preference to K − Cl + and Na − Cl + .
Solution Summary: The author explains that the energy change for the given reactions needs to be determined by the information of the ionization enthalpy and electron affinity.
Part I.
a)
Draw reaction mechanism for the transformations of benzophenone to benzopinacol to benzopinaco lone
b) Pinacol (2,3-dimethyl, 1-3-butanediol) on treatment w/ acid gives a mixture of pina colone
(3,3-dimethyl-2-butanone) and 2, 3-dimethyl - 1,3-butadiene. Give reasonable mechanism
the formation of
the products
For
3. The explosive decomposition of 2 mole of TNT (2,4,6-trinitrotoluene) is shown below:
Assume the C(s) is soot-basically atomic carbon (although it isn't actually atomic carbon in real life).
2
CH3
H
NO2
NO2
3N2 (g)+7CO (g) + 5H₂O (g) + 7C (s)
H
a. Use bond dissociation energies to calculate how much AU is for this reaction in kJ/mol.
Part I.
Draw reaction mechanism for the transformations of benzophenone to benzopinacol to benzopinaco lone and answer the ff:
Pinacol (2,3-dimethyl, 1-3-butanediol) on treatment w/ acid gives a mixture of pina colone
and
(3,3-dimethyl-2-butanone) 2,3-dimethyl-1,3-butadiene. Give reasonable mechanism
the formation of the products
For
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Atomic Number, Atomic Mass, and the Atomic Structure | How to Pass ChemistryThe Nucleus: Crash Course Chemistry #1; Author: Crash Course;https://www.youtube.com/watch?v=FSyAehMdpyI;License: Standard YouTube License, CC-BY