EBK INQUIRY INTO PHYSICS
8th Edition
ISBN: 8220103599450
Author: Ostdiek
Publisher: Cengage Learning US
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Chapter 3, Problem 21Q
To determine
The energy conversion if a rubber ball is held at an eye level and when dropped, it will bounce back, but not to its original height.
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A proton moves at 5.20 × 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 8.40 × 103 N/C. Ignore any gravitational effects.
(a) Find the time interval required for the proton to travel 6.00 cm horizontally.
83.33
☑
Your response differs from the correct answer by more than 10%. Double check your calculations. ns
(b) Find its vertical displacement during the time interval in which it travels 6.00 cm horizontally. (Indicate direction with the sign of your answer.)
2.77
Your response differs from the correct answer by more than 10%. Double check your calculations. mm
(c) Find the horizontal and vertical components of its velocity after it has traveled 6.00 cm horizontally.
5.4e5
V
×
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. I + [6.68e4
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each…
(1)
Fm
Fmn
mn
Fm
B
W₁
e
Fmt
W
0
Fit
Wt
0
W
Fit
Fin
n
Fmt
n
As illustrated in Fig.
consider the
person
performing extension/flexion movements of the lower leg
about the knee joint (point O) to investigate the forces and
torques produced by muscles crossing the knee joint. The
setup of the experiment is described in Example
above.
The geometric parameters of the model under investigation,
some of the forces acting on the lower leg and its free-body
diagrams are shown in Figs. and For this system, the
angular displacement, angular velocity, and angular accelera-
tion of the lower leg were computed using data obtained
during the experiment such that at an instant when 0 = 65°,
@ = 4.5 rad/s, and a = 180 rad/s². Furthermore, for this sys-
tem assume that a = 4.0 cm, b = 23 cm, ß = 25°, and the net
torque generated about the knee joint is M₁ = 55 Nm. If the
torque generated about the knee joint by the weight of the lower
leg is Mw 11.5 Nm, determine:
=
The moment arm a of Fm relative to the…
The figure shows a particle that carries a charge of 90 = -2.50 × 106 C. It is moving along the +y
->
axis at a speed of v = 4.79 × 106 m/s. A magnetic field B of magnitude 3.24 × 10-5 T is directed
along the +z axis, and an electric field E of magnitude 127 N/C points along the -x axis.
Determine (a) the magnitude and (b) direction (as an angle within x-y plane with respect to +x-
axis in the range (-180°, 180°]) of the net force that acts on the particle.
+x
+z
AB
90
+y
Chapter 3 Solutions
EBK INQUIRY INTO PHYSICS
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