a. Query: select memb_no, name from member natural join borrowed where isbn in (select isbn from book where publisher=’McGraw-Hill’); Explanation:

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Answer 1

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Chapter 3, Problem 21E

Explanation of Solution

a.

Query:

select memb_no, name from member natural join borrowed where isbn in (select isbn from book where publisher=’McGraw-Hill’);

Explanation:

Explanation of Solution

b.

Query:

Select memb_no, name from member m where not exists

(select isbn from book where publisher=’McGraw-Hill’ except (select isbn from member natural join borrowed where m.memb_no=memb_no));

Explanation:

The above query is get the “memb_n...

Explanation of Solution

c.

Query:

Select memb_no, name from member natural join borrowed natural join book group by memb_no, name, publisher having count (isbn)>5...

Explanation of Solution

d.

Query:

select sum(num_of_books)/ count(memb_no) from (select memb_no, (select count(*) from borrowed where member.memdber_no=borrowed...

Explanation of Solution

e.

Query:

create table participated (report_number char(20) primary key, license char(20) references car, driver_id char(20) references driver, damage_amount dec(6,2) )

Explanation:

The above query is used creat...

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Answer the question fully and accurately by providing the required files(Java Code, Two output files and written answers to questions 1-3 in a word document)meaning question 1 to 3 also provide correct answers for those questions.(note: this quetion is not graded).

.NET Interactive Solving Sudoku using Grover's Algorithm We will now solve a simple problem using Grover's algorithm, for which we do not necessarily know the solution beforehand. Our problem is a 2x2 binary sudoku, which in our case has two simple rules: •No column may contain the same value twice •No row may contain the same value twice If we assign each square in our sudoku to a variable like so: 1 V V₁ V3 V2 we want our circuit to output a solution to this sudoku. Note that, while this approach of using Grover's algorithm to solve this problem is not practical (you can probably find the solution in your head!), the purpose of this example is to demonstrate the conversion of classical decision problems into oracles for Grover's algorithm. Turning the Problem into a Circuit We want to create an oracle that will help us solve this problem, and we will start by creating a circuit that identifies a correct solution, we simply need to create a classical function on a quantum circuit that…

Answer 2

Expert Solution & Answer

Chapter 3, Problem 21E

Explanation of Solution

a.

Query:

select memb_no, name from member natural join borrowed where isbn in (select isbn from book where publisher=’McGraw-Hill’);

Explanation:

Explanation of Solution

b.

Query:

Select memb_no, name from member m where not exists

(select isbn from book where publisher=’McGraw-Hill’ except (select isbn from member natural join borrowed where m.memb_no=memb_no));

Explanation:

The above query is get the “memb_n...

Explanation of Solution

c.

Query:

Select memb_no, name from member natural join borrowed natural join book group by memb_no, name, publisher having count (isbn)>5...

Explanation of Solution

d.

Query:

select sum(num_of_books)/ count(memb_no) from (select memb_no, (select count(*) from borrowed where member.memdber_no=borrowed...

Explanation of Solution

e.

Query:

create table participated (report_number char(20) primary key, license char(20) references car, driver_id char(20) references driver, damage_amount dec(6,2) )

Explanation:

The above query is used creat...

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Answer 3

Expert Solution & Answer

Chapter 3, Problem 21E

Explanation of Solution

a.

Query:

select memb_no, name from member natural join borrowed where isbn in (select isbn from book where publisher=’McGraw-Hill’);

Explanation:

Explanation of Solution

b.

Query:

Select memb_no, name from member m where not exists

(select isbn from book where publisher=’McGraw-Hill’ except (select isbn from member natural join borrowed where m.memb_no=memb_no));

Explanation:

The above query is get the “memb_n...

Explanation of Solution

c.

Query:

Select memb_no, name from member natural join borrowed natural join book group by memb_no, name, publisher having count (isbn)>5...

Explanation of Solution

d.

Query:

select sum(num_of_books)/ count(memb_no) from (select memb_no, (select count(*) from borrowed where member.memdber_no=borrowed...

Explanation of Solution

e.

Query:

create table participated (report_number char(20) primary key, license char(20) references car, driver_id char(20) references driver, damage_amount dec(6,2) )

Explanation:

The above query is used creat...

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Answer 4

Expert Solution & Answer

Chapter 3, Problem 21E

Explanation of Solution

a.

Query:

select memb_no, name from member natural join borrowed where isbn in (select isbn from book where publisher=’McGraw-Hill’);

Explanation:

Explanation of Solution

b.

Query:

Select memb_no, name from member m where not exists

(select isbn from book where publisher=’McGraw-Hill’ except (select isbn from member natural join borrowed where m.memb_no=memb_no));

Explanation:

The above query is get the “memb_n...

Explanation of Solution

c.

Query:

Select memb_no, name from member natural join borrowed natural join book group by memb_no, name, publisher having count (isbn)>5...

Explanation of Solution

d.

Query:

select sum(num_of_books)/ count(memb_no) from (select memb_no, (select count(*) from borrowed where member.memdber_no=borrowed...

Explanation of Solution

e.

Query:

create table participated (report_number char(20) primary key, license char(20) references car, driver_id char(20) references driver, damage_amount dec(6,2) )

Explanation:

The above query is used creat...

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 5

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Answer 6

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Answer 7

Chapter 3, Problem 21E

Explanation of Solution

a.

Query:

select memb_no, name from member natural join borrowed where isbn in (select isbn from book where publisher=’McGraw-Hill’);

Explanation:

Explanation of Solution

b.

Query:

Select memb_no, name from member m where not exists

(select isbn from book where publisher=’McGraw-Hill’ except (select isbn from member natural join borrowed where m.memb_no=memb_no));

Explanation:

The above query is get the “memb_n...

Explanation of Solution

c.

Query:

Select memb_no, name from member natural join borrowed natural join book group by memb_no, name, publisher having count (isbn)>5...

Explanation of Solution

d.

Query:

select sum(num_of_books)/ count(memb_no) from (select memb_no, (select count(*) from borrowed where member.memdber_no=borrowed...

Explanation of Solution

e.

Query:

create table participated (report_number char(20) primary key, license char(20) references car, driver_id char(20) references driver, damage_amount dec(6,2) )

Explanation:

The above query is used creat...

Answer 8

Chapter 3, Problem 21E

Explanation of Solution

a.

Query:

select memb_no, name from member natural join borrowed where isbn in (select isbn from book where publisher=’McGraw-Hill’);

Explanation:

Answer 9

Chapter 3, Problem 21E

Explanation of Solution

a.

Query:

select memb_no, name from member natural join borrowed where isbn in (select isbn from book where publisher=’McGraw-Hill’);

Explanation:

Answer 10

Explanation of Solution

b.

Query:

Select memb_no, name from member m where not exists

(select isbn from book where publisher=’McGraw-Hill’ except (select isbn from member natural join borrowed where m.memb_no=memb_no));

Explanation:

The above query is get the “memb_n...

Answer 11

Explanation of Solution

b.

Query:

Select memb_no, name from member m where not exists

(select isbn from book where publisher=’McGraw-Hill’ except (select isbn from member natural join borrowed where m.memb_no=memb_no));

Explanation:

The above query is get the “memb_n...

Answer 12

Explanation of Solution

c.

Query:

Select memb_no, name from member natural join borrowed natural join book group by memb_no, name, publisher having count (isbn)>5...

Answer 13

Explanation of Solution

c.

Query:

Select memb_no, name from member natural join borrowed natural join book group by memb_no, name, publisher having count (isbn)>5...

Answer 14

Explanation of Solution

d.

Query:

select sum(num_of_books)/ count(memb_no) from (select memb_no, (select count(*) from borrowed where member.memdber_no=borrowed...

Answer 15

Explanation of Solution

d.

Query:

select sum(num_of_books)/ count(memb_no) from (select memb_no, (select count(*) from borrowed where member.memdber_no=borrowed...

Answer 16

Explanation of Solution

e.

Query:

create table participated (report_number char(20) primary key, license char(20) references car, driver_id char(20) references driver, damage_amount dec(6,2) )

Explanation:

The above query is used creat...

Answer 17

Explanation of Solution

e.

Query:

create table participated (report_number char(20) primary key, license char(20) references car, driver_id char(20) references driver, damage_amount dec(6,2) )

Explanation:

The above query is used creat...

Answer 18

Expert Solution & Answer

Answer 19

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Answer 20

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Answer 21

Ch. 3 - Prob. 1PE Ch. 3 - Prob. 2PE Ch. 3 - Prob. 3PE Ch. 3 - Suppose that we have a relation marks(ID, score)...Ch. 3 - Suppose that we have a relation marks(ID, score)...Ch. 3 - The SQL like operator is case sensitive (in most...Ch. 3 - Prob. 7PE Ch. 3 - Prob. 8PE Ch. 3 - Prob. 9PE Ch. 3 - Prob. 10PE

a. Query: select memb_no, name from member natural join borrowed where isbn in (select isbn from book where publisher=’McGraw-Hill’); Explanation:

Explanation of Solution

a. Query: select memb_no, name from member natural join borrowed where isbn in (select isbn from book where publisher=’McGraw-Hill’); Explanation:

Explanation of Solution

b. Query: Select memb_no, name from member m where not exists (select isbn from book where publisher=’McGraw-Hill’ except (select isbn from member natural join borrowed where m.memb_no=memb_no)); Explanation: The above query is get the “memb_n...

Explanation of Solution

c. Query: Select memb_no, name from member natural join borrowed natural join book group by memb_no, name, publisher having count (isbn)>5...

Explanation of Solution

d. Query: select sum(num_of_books)/ count(memb_no) from (select memb_no, (select count(*) from borrowed where member.memdber_no=borrowed...

Explanation of Solution

e. Query: create table participated (report_number char(20) primary key, license char(20) references car, driver_id char(20) references driver, damage_amount dec(6,2) ) Explanation: The above query is used creat...

Want to see the full answer?

Chapter 3 Solutions

a.

Query:

select memb_no, name from member natural join borrowed where isbn in (select isbn from book where publisher=’McGraw-Hill’);

Explanation:

b.

Query:

Select memb_no, name from member m where not exists

(select isbn from book where publisher=’McGraw-Hill’ except (select isbn from member natural join borrowed where m.memb_no=memb_no));

Explanation:

The above query is get the “memb_n...

c.

Query:

Select memb_no, name from member natural join borrowed natural join book group by memb_no, name, publisher having count (isbn)>5...

d.

Query:

select sum(num_of_books)/ count(memb_no) from (select memb_no, (select count(*) from borrowed where member.memdber_no=borrowed...

e.

Query:

create table participated (report_number char(20) primary key, license char(20) references car, driver_id char(20) references driver, damage_amount dec(6,2) )

Explanation:

The above query is used creat...