AUTOMOTIVE TECHNOLOGY -W/MINDTAP ACCESS
7th Edition
ISBN: 9780357096789
Author: ERJAVEC
Publisher: CENGAGE L
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Chapter 3, Problem 1SA
Describe Newton’s first law of motion and give an application of this law in automotive theory.
Expert Solution & Answer
To determine
Newton’s first law of motion with an application in terms of automotive theory.
Answer to Problem 1SA
Newton’s first law of motion or Newton’s law of inertia: “Every object in its state of rest or uniform motion(Acceleration is zero) in a straight line unless it is compelled to change that state by forces impressed on it”.
Explanation of Solution
When an object is in rest or motion, that object will always be in rest or motion until an external force work on that object.
Example: Assume a car is in rest, the car will be in rest until the force applied. Now the car is moving, and this car will be moving until the force applied on it.
Conclusion:
Newton’s first law of motion is working every condition when any object is in rest or trying to rest.
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Students have asked these similar questions
Example 8: 900 Kg dry solid per hour is
dried in a counter current continues dryer
from 0.4 to 0.04 Kg H20/Kg wet solid
moisture content. The wet solid enters the
dryer at 25 °C and leaves at 55 °C. Fresh
air at 25 °C and 0.01Kg vapor/Kg dry air is
mixed with a part of the moist air leaving
the dryer and heated to a temperature of
130 °C in a finned air heater and enters the
dryer with 0.025 Kg/Kg alry air. Air leaving
the dryer at 85 °C and have a humidity
0.055 Kg vaper/Kg dry air. At equilibrium
the wet solid weight is 908 Kg solid per
hour.
*=0.0088
Calculate:- Heat loss from the dryer and
the rate of fresh air.
Take the specific heat of the solid
and moisture are 980 and 4.18J/Kg.K
respectively,
A. =2500 KJ/Kg.
Humid heat at 0.01 Kg vap/Kg dry=1.0238
KJ/Kg. "C. Humid heat at 0.055 Kg/Kg
1.1084 KJ/Kg. "C
2.8
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Can you solve the question by finding initial angular acceleration of D then ueing it to calculate angular velocity of D.
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العنوان
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Jon
14.23. A double-effect forward-feed
evaporator is required to give a product
consisting of 30 per cent crystals and a
mother liquor containing 40 per cent by
mass of dissolved solids. Heat transfer
coefficients are 2.8 and 1.7 kW/m² K in the
first and second effects respectively. Dry
saturated steam is supplied at 375 kN/m²
and the condenser operates at 13.5 kN/
m².
(a) What area of heating surface is
required in each effect assuming the
effects are identical, if the feed rate is 0.6
kg/s of liquor, containing 20 per cent by
mass of dissolved solids, and the feed
temperature is 313 K?
(b) What is the pressure above the boiling
liquid in the first effect?
The specific heat capacity may be
taken as constant at 4.18 kJ/kg K. and
the effects of boiling-point rise and of
hydrostatic head may be neglected.
Chapter 3 Solutions
AUTOMOTIVE TECHNOLOGY -W/MINDTAP ACCESS
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- Example(2): Double effect evaporator is used for concentrating a certain caustic soda solution 10000kg/hr from 9wt% to 47wt%. The feed at 30°C enters the first evaporator. Backward arrangement evaporators are used. steam is available at 167.7°C and the vapor space in the second effect is 14.6Kpa. The overall heat transfer coefficients of the two effects are 8380 and 6285kcal/ W.CH ork -conce -SOLFFF and-ans.. 112.1 а DiD 3 respectively and the specific heat capacity of all caustic soda solution 3.771 KJ/Kg. °C, determine the heat transfer area of each effect معدلة 5:48 م Oarrow_forwardgive me solution math not explinarrow_forwardgive me solution math not explinarrow_forward
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