Concept explainers
a)
The x -intercept of the given graph.
a)
![Check Mark](/static/check-mark.png)
Answer to Problem 1MCP
Solution:
The x -intercept is 4.
Explanation of Solution
Given:
The graph of the line.
Concept used:
To find the x -intercept of a given line on a graph, the point where the line is intersecting the x - axis is the x -intercept and the point where the line is intersecting the y axis is the y -intercept.
Calculation:
From the given graph, we observe that the line is intersecting x - axis at
Conclusion:
Therefore, the x -intercept of the graph is 4.
b)
The y -intercept in the graph given below.
b)
![Check Mark](/static/check-mark.png)
Answer to Problem 1MCP
Solution:
y -intercept is 2.
Explanation of Solution
Given:
The graph of the line.
Concept used:
To find the x -intercept of a given line on a graph, the point where the line is intersecting the x - axis is the x -intercept and the point where the line is intersecting the y axis is the y -intercept.
Calculation:
The line is intersecting y - axis at 2, which makes it the y -intercept.
Conclusion:
Therefore, the y -intercept of the given line is 2.
c)
The slope of the line given in the graph.
c)
![Check Mark](/static/check-mark.png)
Answer to Problem 1MCP
Solution:
The line’s slope is:
Explanation of Solution
Concept used:
Follow the below process for find the slope the given line:
Pick two points on the line and determine their coordinates.
Determine rise: the difference in y -coordinates of these two points.
Determine run: the difference in x -coordinates for these two points.
Divide the difference in y -coordinates by the difference in x -coordinates (rise/run or slope).
Calculation:
For slope, consider the two points
Difference in y -coordinates for these two points
Difference in x -coordinates for these two points
Now, divide the difference in y -coordinates by the difference in x -coordinates and get,
Conclusion:
Therefore, the slope of the graph is
Want to see more full solutions like this?
Chapter 3 Solutions
MyLab Math with Pearson eText -- Access Card -- for Introductory and Intermediate Algebra for College Students (18-Weeks)
- Write a quadratic equation in factored form that has solutions of x = 2 and x = = -3/5 ○ a) (x-2)(5x + 3) = 0 ○ b) (x + 2)(3x-5) = 0 O c) (x + 2)(5x -3) = 0 ○ d) (x-2)(3x + 5) = 0arrow_forwardA vacant lot is being converted into a community garden. The garden and a walkway around its perimeter have an area of 690 square feet. Find the width of the walkway (x) if the garden measures 14 feet wide by 18 feet long. Write answer to 2 decimal places. (Write the number without units). Hint: add 2x to each of the garden dimensions of 14 x 18 feet to get the total area for the length multiplied by width.arrow_forwardSolve x-1 x+2 = 12 3 4 Your Answer: Answerarrow_forward
- Find the solutions to the following equation 21x²+5x=6 ○ a) -3/7, 3/2 ☐ b) -2/3, 3/7 ○ c) -7/3, 3/2 ○ d) -2/3, 7/3arrow_forwardListen Solve the quadratic equation. Write the one solution, do not write x =. 2 x²+6x+9= 0 বarrow_forwardSolve the rational equation 14 1 + x-6 x x-7 x-7 ○ a) x = 1, x = 8 ○ b) x = 1 ○ c) x = 7 ○ d) x = 1, x = 7arrow_forward
- Solve the absolute inequality | x + 5 > 3 ○ a) (-∞, -8] U[-2, ∞0) ☐ b) (-8, -2) c) (-2, ∞0) ○ d) (-∞, - 8) U(-2, ∞0)arrow_forward1) Listen Describe the error in the problem X 3 X x 3 - 2 = 25x = 0 25x 25 x = ±5arrow_forwardA falling object travels a distance given by the formula d = 6t + 7t² where d is in feet and t is the time in seconds. How many seconds will it take for the object to travel 115 feet? Round answer to 2 decimal places. (Write the number, not the units). Your Answer:arrow_forward
- Listen Solve the quadratic equation. Write the smaller answer first. 2 Xx - 5x = 24 x = Α x =arrow_forwardSolve the absolute equation |2x = 4| = 10 ○ a) x = -7, x = 3 ○ b) x = -2, x = 6 ○ c) x = -3, x = 7 ○ d) x = 7arrow_forwardFind a rational inequality that has the solution set (-2, 5] О a) x-5 x+2 b) x+5 x-2 ΛΙ ≥ 0 < 0 VI О c) x-5 x+2 ≤0 VI ○ d) x +2 x-5 <0arrow_forward
- Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSONContemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage LearningLinear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
- Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSONIntroduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge PressCollege Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education
![Text book image](https://www.bartleby.com/isbn_cover_images/9780134463216/9780134463216_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305657960/9781305657960_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285463247/9781285463247_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780135163078/9780135163078_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780980232776/9780980232776_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780077836344/9780077836344_smallCoverImage.gif)