MyLab Math with Pearson eText -- Access Card -- for Introductory and Intermediate Algebra for College Students (18-Weeks)
MyLab Math with Pearson eText -- Access Card -- for Introductory and Intermediate Algebra for College Students (18-Weeks)
6th Edition
ISBN: 9780136554196
Author: ROBERT BLITZER
Publisher: Pearson Education (US)
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Chapter 3, Problem 1MCP

a)

To determine

The x -intercept of the given graph.

a)

Expert Solution
Check Mark

Answer to Problem 1MCP

Solution:

The x -intercept is 4.

Explanation of Solution

Given:

The graph of the line.

MyLab Math with Pearson eText -- Access Card -- for Introductory and Intermediate Algebra for College Students (18-Weeks), Chapter 3, Problem 1MCP , additional homework tip 1

Concept used:

To find the  x -intercept of a given line on a graph, the point where the line is intersecting the x - axis is the x -intercept and the point where the line is intersecting the y axis is the y -intercept.

Calculation:

From the given graph, we observe that the line is intersecting x - axis at x=4 . Therefore, the x- intercept of the line is at (4, 0) .

Conclusion:

Therefore, the x -intercept of the graph is 4.

b)

To determine

The y -intercept in the graph given below.

b)

Expert Solution
Check Mark

Answer to Problem 1MCP

Solution:

y -intercept is 2.

Explanation of Solution

Given:

The graph of the line.

MyLab Math with Pearson eText -- Access Card -- for Introductory and Intermediate Algebra for College Students (18-Weeks), Chapter 3, Problem 1MCP , additional homework tip 2

Concept used:

To find the  x -intercept of a given line on a graph, the point where the line is intersecting the x - axis is the x -intercept and the point where the line is intersecting the y axis is the y -intercept.

Calculation:

The line is intersecting y - axis at 2, which makes it the y -intercept.

Conclusion:

Therefore, the y -intercept of the given line is 2.

c)

To determine

The slope of the line given in the graph.

MyLab Math with Pearson eText -- Access Card -- for Introductory and Intermediate Algebra for College Students (18-Weeks), Chapter 3, Problem 1MCP , additional homework tip 3

c)

Expert Solution
Check Mark

Answer to Problem 1MCP

Solution:

The line’s slope is: −12

Explanation of Solution

Concept used:

Follow the below process for find the slope the given line:

Pick two points on the line and determine their coordinates.

Determine rise: the difference in y -coordinates of these two points.

Determine run: the difference in x -coordinates for these two points.

Divide the difference in y -coordinates by the difference in x -coordinates (rise/run or slope).

Calculation:

For slope, consider the two points (0,2) and (4, 0) on the graph.

Difference in y -coordinates for these two points (0,2) and (4, 0) : 2−0=2 .

Difference in x -coordinates for these two points (0,2) and (4, 0) : 0−4=−4 .

Now, divide the difference in y -coordinates by the difference in x -coordinates and get,

  2−00−4=−24=−12

Conclusion:

Therefore, the slope of the graph is −12 .

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Chapter 3 Solutions

MyLab Math with Pearson eText -- Access Card -- for Introductory and Intermediate Algebra for College Students (18-Weeks)

Ch. 3.1 - Fill in the blank so that the resulting statement...Ch. 3.1 - Fill in each blank so that the resulting statement...Ch. 3.1 - Prob. 3CAVCCh. 3.1 - Prob. 4CAVCCh. 3.1 - Prob. 5CAVCCh. 3.1 - Prob. 6CAVCCh. 3.1 - Prob. 7CAVCCh. 3.1 - Prob. 8CAVCCh. 3.1 - Plot the given point in a rectangular coordinate...Ch. 3.1 - Prob. 2ES
Ch. 3.1 - Prob. 3ESCh. 3.1 - Prob. 4ESCh. 3.1 - Prob. 5ESCh. 3.1 - Prob. 6ESCh. 3.1 - Prob. 7ESCh. 3.1 - Prob. 8ESCh. 3.1 - Prob. 9ESCh. 3.1 - Prob. 10ESCh. 3.1 - Prob. 11ESCh. 3.1 - 12. 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