To rank: The speed of the projectile motion from largest to smallest.

Question

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Answer 1

Question

Chapter 3, Problem 1FC

To determine

To rank: The speed of the projectile motion from largest to smallest.

Expert Solution & Answer

Answer to Problem 1FC

The correct option is, “ (a). v1>v3>v2_ ”.

Explanation of Solution

In a projectile motion, the horizontal component of velocity of a given motion remains constant. This is because the acceleration of the motion is zero in the horizontal direction. However, there is a change in the vertical component of velocity in a projectile motion.

In the given figure, at point 1, the vertical component of velocity is maximum; at point 2, the vertical component is zero as it is at the top of the trajectory; and at point 3, there is an increase in the vertical component of velocity but less than that at point 1.

Therefore, the rank them in order of the speed as follows: v1>v3>v2 .

Conclusion:

Hence, the correct option is, “ (a). v1>v3>v2_ ”.

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Answer 2

Question

Chapter 3, Problem 1FC

To determine

To rank: The speed of the projectile motion from largest to smallest.

Expert Solution & Answer

Answer to Problem 1FC

The correct option is, “ (a). v1>v3>v2_ ”.

Explanation of Solution

In a projectile motion, the horizontal component of velocity of a given motion remains constant. This is because the acceleration of the motion is zero in the horizontal direction. However, there is a change in the vertical component of velocity in a projectile motion.

In the given figure, at point 1, the vertical component of velocity is maximum; at point 2, the vertical component is zero as it is at the top of the trajectory; and at point 3, there is an increase in the vertical component of velocity but less than that at point 1.

Therefore, the rank them in order of the speed as follows: v1>v3>v2 .

Conclusion:

Hence, the correct option is, “ (a). v1>v3>v2_ ”.

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Answer 3

Question

Chapter 3, Problem 1FC

To determine

To rank: The speed of the projectile motion from largest to smallest.

Expert Solution & Answer

Answer to Problem 1FC

The correct option is, “ (a). v1>v3>v2_ ”.

Explanation of Solution

In a projectile motion, the horizontal component of velocity of a given motion remains constant. This is because the acceleration of the motion is zero in the horizontal direction. However, there is a change in the vertical component of velocity in a projectile motion.

In the given figure, at point 1, the vertical component of velocity is maximum; at point 2, the vertical component is zero as it is at the top of the trajectory; and at point 3, there is an increase in the vertical component of velocity but less than that at point 1.

Therefore, the rank them in order of the speed as follows: v1>v3>v2 .

Conclusion:

Hence, the correct option is, “ (a). v1>v3>v2_ ”.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 3, Problem 1FC

To determine

To rank: The speed of the projectile motion from largest to smallest.

Expert Solution & Answer

Answer to Problem 1FC

The correct option is, “ (a). v1>v3>v2_ ”.

Explanation of Solution

In a projectile motion, the horizontal component of velocity of a given motion remains constant. This is because the acceleration of the motion is zero in the horizontal direction. However, there is a change in the vertical component of velocity in a projectile motion.

In the given figure, at point 1, the vertical component of velocity is maximum; at point 2, the vertical component is zero as it is at the top of the trajectory; and at point 3, there is an increase in the vertical component of velocity but less than that at point 1.

Therefore, the rank them in order of the speed as follows: v1>v3>v2 .

Conclusion:

Hence, the correct option is, “ (a). v1>v3>v2_ ”.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 3, Problem 1FC

To determine

To rank: The speed of the projectile motion from largest to smallest.

Expert Solution & Answer

Answer to Problem 1FC

The correct option is, “ (a). v1>v3>v2_ ”.

Explanation of Solution

In a projectile motion, the horizontal component of velocity of a given motion remains constant. This is because the acceleration of the motion is zero in the horizontal direction. However, there is a change in the vertical component of velocity in a projectile motion.

In the given figure, at point 1, the vertical component of velocity is maximum; at point 2, the vertical component is zero as it is at the top of the trajectory; and at point 3, there is an increase in the vertical component of velocity but less than that at point 1.

Therefore, the rank them in order of the speed as follows: v1>v3>v2 .

Conclusion:

Hence, the correct option is, “ (a). v1>v3>v2_ ”.

Answer 6

Chapter 3, Problem 1FC

To determine

To rank: The speed of the projectile motion from largest to smallest.

Expert Solution & Answer

Answer to Problem 1FC

The correct option is, “ (a). v1>v3>v2_ ”.

Explanation of Solution

In a projectile motion, the horizontal component of velocity of a given motion remains constant. This is because the acceleration of the motion is zero in the horizontal direction. However, there is a change in the vertical component of velocity in a projectile motion.

In the given figure, at point 1, the vertical component of velocity is maximum; at point 2, the vertical component is zero as it is at the top of the trajectory; and at point 3, there is an increase in the vertical component of velocity but less than that at point 1.

Therefore, the rank them in order of the speed as follows: v1>v3>v2 .

Conclusion:

Hence, the correct option is, “ (a). v1>v3>v2_ ”.

Answer 7

Chapter 3, Problem 1FC

To determine

To rank: The speed of the projectile motion from largest to smallest.

Answer 8

Expert Solution & Answer

Answer to Problem 1FC

The correct option is, “ (a). v1>v3>v2_ ”.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

In a projectile motion, the horizontal component of velocity of a given motion remains constant. This is because the acceleration of the motion is zero in the horizontal direction. However, there is a change in the vertical component of velocity in a projectile motion.

In the given figure, at point 1, the vertical component of velocity is maximum; at point 2, the vertical component is zero as it is at the top of the trajectory; and at point 3, there is an increase in the vertical component of velocity but less than that at point 1.

Therefore, the rank them in order of the speed as follows: v1>v3>v2 .

Conclusion:

Hence, the correct option is, “ (a). v1>v3>v2_ ”.