Chapter 3, Problem 1FC

To determine

To rank: The speed of the projectile motion from largest to smallest.

Answer to Problem 1FC

The correct option is, “ $\underset{\_}{\left(\text{a}\right).v_1>v_3>v_2}$”.

Explanation of Solution

In a projectile motion, the horizontal component of velocity of a given motion remains constant. This is because the acceleration of the motion is zero in the horizontal direction. However, there is a change in the vertical component of velocity in a projectile motion.

In the given figure, at point 1, the vertical component of velocity is maximum; at point 2, the vertical component is zero as it is at the top of the trajectory; and at point 3, there is an increase in the vertical component of velocity but less than that at point 1.

Therefore, the rank them in order of the speed as follows: $v_1>v_3>v_2$.

Conclusion:

Hence, the correct option is, “ $\underset{\_}{\left(\text{a}\right).v_1>v_3>v_2}$”.