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Mathematics For Machine Technology
8th Edition
ISBN: 9781337798310
Author: Peterson, John.
Publisher: Cengage Learning,
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Textbook Question
Chapter 3, Problem 1A
Determine the least common denominator of
Expert Solution & Answer
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To determine
The least common denominator.
Answer to Problem 1A
The least common denominator is, 24
Explanation of Solution
Given:
Some digits are given in the problem:
Calculation:
Now we calculate the least common multiple (LCM) for given denominators (3,8 and 12)
The least common multiple (LCM) for given denominators (3,8 and 12)is 24
Hence, the least common denominator is, 24
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Use the Cauchy Riemann equations (polar form version).
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QUESTION 4
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Chapter 3 Solutions
Mathematics For Machine Technology
Ch. 3 - Determine the least common denominator of 23,58,...Ch. 3 - Express 14,56, and 712as equivalent fractions...Ch. 3 - Express 298 as a mixed number.Ch. 3 - Express the mixed number 516as an improper...Ch. 3 - Add 512+34+16 .Ch. 3 - Add 238+134+513 .Ch. 3 - Subtract each of the fractions in Exercises 7...Ch. 3 - Subtract each of the fractions in Exercises 7...Ch. 3 - Subtract each of the fractions in Exercises 7...Ch. 3 - Prob. 10A
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- Question 3 a. Using Laplace theorem, find the determinant of the following matrix. 3 5 2 4 1 3 7 6 A= 2 48 3 569 7arrow_forwardChoose all of the statements that are true: 16 is even -16 is even 401 is even √2 is even π is even 2π is even If n is an integer, then n(n + 1) is always even.arrow_forwardIs the number "-4" even, odd, or neither? Use the definition of even/odd to explain why your answer makes sense.arrow_forward
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- not use ai pleasearrow_forwardPidgeonhole Principle 1. The floor of x, written [x], also called the integral part, integer part, or greatest integer, is defined as the greatest integer less than or equal to x. Similarly the ceiling of x, written [x], is the smallest integer greater than or equal to x. Try figuring out the answers to the following: (a) [2.1] (b) [2] (c) [2.9] (d) [2.1] (e) [2] (f) [2.9] 2. The simple pidgeonhole principle states that, if you have N places and k items (k> N), then at least one hole must have more than one item in it. We tried this with chairs and students: Assume you have N = 12 chairs and k = 18 students. Then at least one chair must have more than one student on it. 3. The general pidgeonhole principle states that, if you have N places and k items, then at least one hole must have [] items or more in it. Try this out with (a) n = 10 chairs and k = 15 students (b) n = 10 chairs and k = 23 students (c) n = 10 chairs and k = 20 students 4. There are 34 problems on these pages, and we…arrow_forwardDetermine if the set of vectors is linearly independent or linearly dependent. linearly independent O linearly dependent Save Answer Q2.2 1 Point Determine if the set of vectors spans R³. they span R³ they do not span R³ Save Answer 23 Q2.3 1 Point Determine if the set of vectors is linearly independent or linearly dependent. linearly independent O linearly dependent Save Answer 1111 1110 Q2.4 1 Point Determine if the set of vectors spans R4. O they span R4 they do not span IR4 1000; 111O'arrow_forward
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