EBK PHYSICS FOR SCIENTISTS & ENGINEERS
5th Edition
ISBN: 9780134296074
Author: GIANCOLI
Publisher: VST
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II. The position coordinate of a
particle which is confined to
move along a straight line is
given by s = 2t3 – 24t + 6,
where s is measured in meters
from a convenient origin and t
is in seconds. Determine (a)
the time required for the
particle to reach a velocity of
72 m/s from its initial condition
at t = 0, (b) the acceleration of
the particle when v = 30 m/s,
and © the net displacement of
the particle during the interval
t = 1s and t = 4s. (Practice at
Home)
(1) The position of a particle for 1> 0 is given by F(t)= (3.0r i-7.0r j-5.01 k) m. (a) What
is the velocity as a function of time? (b) What is the acceleration as a function of time? (c) What
is the particle's velocity at /- 2.0 s? (d) What is its speed at t= 1.0 s and / 3.0 s? (e) What is
the average velocity between t-1.0s and r= 2.0 s?
An object is moving along the x axis and an 18.0 s record of its position as a function of time is shown in the graph.
х (m)
32
20
8
t (s)
3 6 9
12
15
18
(a) Determine the position x(t) of the object at the following times.
t = 0.0, 3.00 s, 9.00 s, and 18.0 s
x(t = 0) =
x(t = 3.00 s) =
m
x(t = 9.00 s) =
x(t = 18.0 s) =
(b) Determine the displacement Ax of the object for the following time intervals. (Indicate the direction with the sign of your answer.)
At = (0
→ 6.00 s), (6.00 s → 12.0 s), (12.0 s → 18.0 s), and (0 → 18.0 s)
Ax(0 → 6.00 s) =
Дx (6.00 s
→ 12.0 s) =
Ax(12.0 s → 18.0 s) =
%3D
Ax(0 → 18.00 s) =
E E E E
Chapter 3 Solutions
EBK PHYSICS FOR SCIENTISTS & ENGINEERS
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