MODERN PHYSICS F/SCI..-WEBASSIGN(MULTI)
MODERN PHYSICS F/SCI..-WEBASSIGN(MULTI)
4th Edition
ISBN: 9780357644782
Author: Thornton
Publisher: CENGAGE L
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Chapter 3, Problem 14P

(a)

To determine

The wavelengths that lies in the range of 400nm700nm and the name of the series to which they belong.

(a)

Expert Solution
Check Mark

Answer to Problem 14P

The wavelength that lie in the range of 400nm700nm lies in the Balmer series and the wavelengths are 656.9nm,486.6nm,434.4nm&410.5nm.

Explanation of Solution

Write the expression for the Rydberg’s equation.

    1λ=RH(1n21k2)        (I)

Here, λ is the smallest wavelength of emission, RH is the Rydberg’s constant, n is the number of the series of emission and k is the next level up to which the emission occurs.

The number corresponding to the Balmer series of hydrogen spectrum is 2. So, the value for four brightest emission will be 3,4,5&6.

Conclusion:

For Balmer series:

Substitute 2 for n, 3 for k and 1.096×107m1 for RH in equation (I).

  1λ=(1.096×107m1)(122132)λ=11.096×107m1(7.2)m(109nm1m)=656.9nm

Substitute 2 for n, 4 for k and 1.096×107m1 for RH in equation (I).

  1λ=(1.096×107m1)(122142)λ=11.096×107m1(5.33)m(109nm1m)=486.6nm

Substitute 2 for n, 5 for k and 1.096×107m1 for RH in equation (I).

  1λ=(1.096×107m1)(122152)λ=11.096×107m1(4.762)m(109nm1m)=434.4nm

Substitute 2 for n, 6 for k and 1.096×107m1 for RH in equation (I).

  1λ=(1.096×107m1)(122162)λ=11.096×107m1(4.5)m(109nm1m)=410.5nm

Thus, the wavelength that lie in the range of 400nm700nm lies in the Balmer series and the wavelengths are 656.9nm,486.6nm,434.4nm&410.5nm.

(b)

To determine

The reason for the visibility of the only three wavelengths by the detector.

(b)

Expert Solution
Check Mark

Answer to Problem 14P

The three wavelengths are detected by the detector because the detector is moving away from the source and other wavelength is not visible for the detector.

Explanation of Solution

The wavelengths lying in the visible region are the four wavelengths that should be detected by the detector used. Since the detector is moving away from the source, there is a possibility that the highest wavelength of 656nm might have undergone red shift.

Due to red shift, the wavelength would have increased and might have gone out of the visible range of the electromagnetic spectrum.

Conclusion:

Thus, the three wavelengths are detected by the detector because the detector is moving away from the source and other wavelength is not visible for the detector.

(c)

To determine

The speed of the stellar object that emits the spectrum.

(c)

Expert Solution
Check Mark

Answer to Problem 14P

The speed of the moving stellar object is 3×107m/s.

Explanation of Solution

Write the expression for the relation between the observed wavelength and the wavelength from the source.

  λobservedλsource=1+β1β

Simplify and rearrange the above expression for β.

  β=(λobservedλsource)21(λobservedλsource)2+1        (II)

Here, λobserved is the observed wavelength, λsource is the wavelength emitted by the source and β is the relativistic factor.

Write the expression for the speed of the stellar object.

  v=βc        (III)

Here, v is the speed of the object and c is the speed of light.

Conclusion:

Substitute 453.4nm for λoberved and 410.29nm for λsource in equation (II).

  β=(453.4nm410.29nm)21(453.4nm410.29nm)2+1=0.222.22=0.0996

Substitute 0.0996 for β and 3×108m/s for c in equation (III).

  v=(0.0996)(3×108m/s)3×107m/s

Thus, the speed of the moving stellar object is 3×107m/s.

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Chapter 3 Solutions

MODERN PHYSICS F/SCI..-WEBASSIGN(MULTI)

Ch. 3 - Prob. 11QCh. 3 - Prob. 12QCh. 3 - Prob. 13QCh. 3 - Prob. 14QCh. 3 - Prob. 15QCh. 3 - Prob. 16QCh. 3 - Prob. 17QCh. 3 - Prob. 18QCh. 3 - Prob. 19QCh. 3 - Prob. 20QCh. 3 - Prob. 21QCh. 3 - Prob. 22QCh. 3 - Prob. 23QCh. 3 - Prob. 24QCh. 3 - Prob. 25QCh. 3 - Prob. 26QCh. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Across what potential difference does an electron...Ch. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10PCh. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Calculate max for blackbody radiation for (a)...Ch. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - White dwarf stars have been observed with a...Ch. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67PCh. 3 - Prob. 68PCh. 3 - The Fermi Gamma-ray Space Telescope, launched in...Ch. 3 - Prob. 70P
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