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Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Expert Solution & Answer
Chapter 3, Problem 11E
Explanation of Solution
a.
DISTINCT:
“DISTINCT” keyword is used to avoid redundant data (removing duplicate values) from a column. The syntax for “DISTINCT” keyword is as follows:
SELECT DISTINCT column_Name FROM table_Name;
Query:
Select distinct name from student natural join takes natural join course where course...
Explanation of Solution
b.
Query:
Select ID, name from student natural join takes except
Select ID, name from student natural join takes where year<2017
Explanation:
...Explanation of Solution
c.
Query:
Select dept_name, max(salary) from instructor group by dept_name
Explanat...
Explanation of Solution
d.
Query:
Select min(max_sal) from (select dept_name, max(salary) as max_sal from instructor group by dept_name)
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Students have asked these similar questions
8.4 Self-Bias Configuration
20. Determine Zi. Zo. and A,, for the network of Fig. 8.73 if gf, = 3000 μS and gos = 50 μs.
21. Determine Z, Zo, and A, for the network of Fig. 8.73 if the 20-uF capacitor is removed and the
parameters of the network are the same as in Problem 20. Compare results with those of
Problem 20.
+12 V
3.3 ΚΩ
HE
C₂
Vo
Z
Zo
C₁
10 ΜΩ
Z₁
1.1 ΚΩ
Cs 20 µF
FIG. 8.73
Problems 20, 21, 22, and 59.
21. Determine Zi, Zo, and A, for the network of Fig. 8.73 if the 20-μF capacitor is removed and the
parameters of the network are the same as in Problem 20. Compare results with those of
Problem 20.
+12 V
3.3 ΚΩ
+6
C₂
C₁
Z₁
10 ΜΩ
1.1 ΚΩ
Cs
20 μF
FIG. 8.73
Zo
Ninth Edition
Determine Zi, Zo and Av
20 V
Zi
+
1 ΜΩ
2 ΚΩ
HH
Z
IDSS= 6MA
Vp=-6V
Yos = 40μS
20 and 47
Chapter 3 Solutions
Database System Concepts
Ch. 3 - Prob. 1PECh. 3 - Prob. 2PECh. 3 - Prob. 3PECh. 3 -
Suppose that we have a relation marks(ID, score)...Ch. 3 - Suppose that we have a relation marks(ID, score)...Ch. 3 -
The SQL like operator is case sensitive (in most...Ch. 3 - Prob. 7PECh. 3 - Prob. 8PECh. 3 - Prob. 9PECh. 3 - Prob. 10PE
Ch. 3 - Prob. 11ECh. 3 - Prob. 12ECh. 3 - Prob. 13ECh. 3 -
Consider the insurance database of Figure 3.17,...Ch. 3 - Prob. 15ECh. 3 - Prob. 16ECh. 3 - Prob. 17ECh. 3 - Prob. 18ECh. 3 -
List two reasons why null values might be...Ch. 3 - Prob. 20ECh. 3 - Prob. 21ECh. 3 - Prob. 22ECh. 3 - Prob. 23ECh. 3 - Prob. 24ECh. 3 - Prob. 25ECh. 3 - Prob. 26ECh. 3 - Using the university schema, write an SQL query to...Ch. 3 - Prob. 28ECh. 3 - Prob. 29ECh. 3 - Prob. 30ECh. 3 - Prob. 31ECh. 3 - Prob. 32ECh. 3 - Prob. 33ECh. 3 - Prob. 34ECh. 3 - Prob. 35E
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