a) CH 3 (CH 2 ) 29 CH 3 , a component found in paraffin wax is a solid at room temperature while octane is a liquid. Interpretation: The observation that, CH 3 (CH 2 ) 29 CH 3 , a component found in paraffin wax is a solid at room temperature while octane is a liquid is to be explained. Concept introduction: Even in non polar molecules, the attractive dispersion forces are possible, caused by temporary dipoles arising due to the costant change in electon distribution wihin the molecule. These temporary dipoles, though have a fleeting existence are constantly changing. But their cumulative effect may be strong enough to hold the molecule close together so that a substance can be a solid or liquid. To explain: The observation that, CH 3 (CH 2 ) 29 CH 3 , a component found in paraffin wax is a solid at room temperature while octane is a liquid.

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Answer 1

Question

Chapter 2.SE, Problem 65AP

Interpretation Introduction

a) CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Interpretation:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid is to be explained.

Concept introduction:

Even in non polar molecules, the attractive dispersion forces are possible, caused by temporary dipoles arising due to the costant change in electon distribution wihin the molecule. These temporary dipoles, though have a fleeting existence are constantly changing. But their cumulative effect may be strong enough to hold the molecule close together so that a substance can be a solid or liquid.

To explain:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Interpretation Introduction

b) CH₃CH₂CH₂OH has a higher boiling point than CH₄

Interpretation:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Concept introduction:

An attractive interaction between a hydrogen bonded to an electronegative oxygen or nitrogen atom and an unshared electron pair on another oxygen or nitrogrn atom is termed as hydrogen bonding. It is a very strong dipole-dipole interaction that leads to molecular association. These molecules associated through hydrogen bonding will have a high boiling point.

To explain:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Interpretation Introduction

c) CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil- for simplicity you may assume oil is CH₃(CH₂)₄CH₃

Interpretation:

The observation that CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil with molecular formula CH₃(CH₂)₄CH₃.

Concept introduction:

Like dissolves like. A polar molecule will dissolve in another polar solvent. The solubility can also be explained using the formation of hydrogen bonding between the two substances.

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For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. ? NH2 MgBr Will the first product that forms in this reaction create a new CC bond? ○ Yes ○ No MgBr ? Will the first product that forms in this reaction create a new CC bond? O Yes O No Click and drag to start drawing a structure. :☐ G x c olo Ar HE

Predicting As the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C - C bond as its major product: H₂N O H 1. ? 2. H3O+ If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. 0 If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. فا Explanation Check Click and drag to start drawing a structure.

Highlight the chirality (or stereogenic) center(s) in the given compound. A compound may have one or more stereogenic centers. OH OH OH OH OH OH

Answer 2

Question

Chapter 2.SE, Problem 65AP

Interpretation Introduction

a) CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Interpretation:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid is to be explained.

Concept introduction:

Even in non polar molecules, the attractive dispersion forces are possible, caused by temporary dipoles arising due to the costant change in electon distribution wihin the molecule. These temporary dipoles, though have a fleeting existence are constantly changing. But their cumulative effect may be strong enough to hold the molecule close together so that a substance can be a solid or liquid.

To explain:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Interpretation Introduction

b) CH₃CH₂CH₂OH has a higher boiling point than CH₄

Interpretation:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Concept introduction:

An attractive interaction between a hydrogen bonded to an electronegative oxygen or nitrogen atom and an unshared electron pair on another oxygen or nitrogrn atom is termed as hydrogen bonding. It is a very strong dipole-dipole interaction that leads to molecular association. These molecules associated through hydrogen bonding will have a high boiling point.

To explain:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Interpretation Introduction

c) CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil- for simplicity you may assume oil is CH₃(CH₂)₄CH₃

Interpretation:

The observation that CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil with molecular formula CH₃(CH₂)₄CH₃.

Concept introduction:

Like dissolves like. A polar molecule will dissolve in another polar solvent. The solubility can also be explained using the formation of hydrogen bonding between the two substances.

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Answer 3

Question

Chapter 2.SE, Problem 65AP

Interpretation Introduction

a) CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Interpretation:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid is to be explained.

Concept introduction:

Even in non polar molecules, the attractive dispersion forces are possible, caused by temporary dipoles arising due to the costant change in electon distribution wihin the molecule. These temporary dipoles, though have a fleeting existence are constantly changing. But their cumulative effect may be strong enough to hold the molecule close together so that a substance can be a solid or liquid.

To explain:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Interpretation Introduction

b) CH₃CH₂CH₂OH has a higher boiling point than CH₄

Interpretation:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Concept introduction:

An attractive interaction between a hydrogen bonded to an electronegative oxygen or nitrogen atom and an unshared electron pair on another oxygen or nitrogrn atom is termed as hydrogen bonding. It is a very strong dipole-dipole interaction that leads to molecular association. These molecules associated through hydrogen bonding will have a high boiling point.

To explain:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Interpretation Introduction

c) CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil- for simplicity you may assume oil is CH₃(CH₂)₄CH₃

Interpretation:

The observation that CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil with molecular formula CH₃(CH₂)₄CH₃.

Concept introduction:

Like dissolves like. A polar molecule will dissolve in another polar solvent. The solubility can also be explained using the formation of hydrogen bonding between the two substances.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 2.SE, Problem 65AP

Interpretation Introduction

a) CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Interpretation:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid is to be explained.

Concept introduction:

Even in non polar molecules, the attractive dispersion forces are possible, caused by temporary dipoles arising due to the costant change in electon distribution wihin the molecule. These temporary dipoles, though have a fleeting existence are constantly changing. But their cumulative effect may be strong enough to hold the molecule close together so that a substance can be a solid or liquid.

To explain:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Interpretation Introduction

b) CH₃CH₂CH₂OH has a higher boiling point than CH₄

Interpretation:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Concept introduction:

An attractive interaction between a hydrogen bonded to an electronegative oxygen or nitrogen atom and an unshared electron pair on another oxygen or nitrogrn atom is termed as hydrogen bonding. It is a very strong dipole-dipole interaction that leads to molecular association. These molecules associated through hydrogen bonding will have a high boiling point.

To explain:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Interpretation Introduction

c) CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil- for simplicity you may assume oil is CH₃(CH₂)₄CH₃

Interpretation:

The observation that CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil with molecular formula CH₃(CH₂)₄CH₃.

Concept introduction:

Like dissolves like. A polar molecule will dissolve in another polar solvent. The solubility can also be explained using the formation of hydrogen bonding between the two substances.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 2.SE, Problem 65AP

Interpretation Introduction

a) CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Interpretation:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid is to be explained.

Concept introduction:

Even in non polar molecules, the attractive dispersion forces are possible, caused by temporary dipoles arising due to the costant change in electon distribution wihin the molecule. These temporary dipoles, though have a fleeting existence are constantly changing. But their cumulative effect may be strong enough to hold the molecule close together so that a substance can be a solid or liquid.

To explain:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Interpretation Introduction

b) CH₃CH₂CH₂OH has a higher boiling point than CH₄

Interpretation:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Concept introduction:

An attractive interaction between a hydrogen bonded to an electronegative oxygen or nitrogen atom and an unshared electron pair on another oxygen or nitrogrn atom is termed as hydrogen bonding. It is a very strong dipole-dipole interaction that leads to molecular association. These molecules associated through hydrogen bonding will have a high boiling point.

To explain:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Interpretation Introduction

c) CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil- for simplicity you may assume oil is CH₃(CH₂)₄CH₃

Interpretation:

The observation that CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil with molecular formula CH₃(CH₂)₄CH₃.

Concept introduction:

Like dissolves like. A polar molecule will dissolve in another polar solvent. The solubility can also be explained using the formation of hydrogen bonding between the two substances.

Answer 6

Chapter 2.SE, Problem 65AP

Interpretation Introduction

a) CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Interpretation:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid is to be explained.

Concept introduction:

Even in non polar molecules, the attractive dispersion forces are possible, caused by temporary dipoles arising due to the costant change in electon distribution wihin the molecule. These temporary dipoles, though have a fleeting existence are constantly changing. But their cumulative effect may be strong enough to hold the molecule close together so that a substance can be a solid or liquid.

To explain:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Answer 7

Chapter 2.SE, Problem 65AP

Interpretation Introduction

a) CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Interpretation:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid is to be explained.

Concept introduction:

Even in non polar molecules, the attractive dispersion forces are possible, caused by temporary dipoles arising due to the costant change in electon distribution wihin the molecule. These temporary dipoles, though have a fleeting existence are constantly changing. But their cumulative effect may be strong enough to hold the molecule close together so that a substance can be a solid or liquid.

To explain:

The observation that, CH₃(CH₂)₂₉CH₃, a component found in paraffin wax is a solid at room temperature while octane is a liquid.

Answer 8

Interpretation Introduction

b) CH₃CH₂CH₂OH has a higher boiling point than CH₄

Interpretation:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Concept introduction:

An attractive interaction between a hydrogen bonded to an electronegative oxygen or nitrogen atom and an unshared electron pair on another oxygen or nitrogrn atom is termed as hydrogen bonding. It is a very strong dipole-dipole interaction that leads to molecular association. These molecules associated through hydrogen bonding will have a high boiling point.

To explain:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Answer 9

Interpretation Introduction

b) CH₃CH₂CH₂OH has a higher boiling point than CH₄

Interpretation:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Concept introduction:

An attractive interaction between a hydrogen bonded to an electronegative oxygen or nitrogen atom and an unshared electron pair on another oxygen or nitrogrn atom is termed as hydrogen bonding. It is a very strong dipole-dipole interaction that leads to molecular association. These molecules associated through hydrogen bonding will have a high boiling point.

To explain:

The observation CH₃CH₂CH₂OH has a higher boiling point than CH₄.

Answer 10

Interpretation Introduction

c) CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil- for simplicity you may assume oil is CH₃(CH₂)₄CH₃

Interpretation:

The observation that CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil with molecular formula CH₃(CH₂)₄CH₃.

Concept introduction:

Like dissolves like. A polar molecule will dissolve in another polar solvent. The solubility can also be explained using the formation of hydrogen bonding between the two substances.

Answer 11

Interpretation Introduction

c) CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil- for simplicity you may assume oil is CH₃(CH₂)₄CH₃

Interpretation:

The observation that CH₃CO₂H, which is found in vinegar, will dissolve in water but not in oil with molecular formula CH₃(CH₂)₄CH₃.

Concept introduction:

Like dissolves like. A polar molecule will dissolve in another polar solvent. The solubility can also be explained using the formation of hydrogen bonding between the two substances.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 2.1 - Prob. 1P Ch. 2.1 - Prob. 2P Ch. 2.1 - Use the electronegativity values shown in Figure...Ch. 2.1 - Look at the following electrostatic potential map...Ch. 2.2 - Ethylene glycol, HOCH2CH2OH, may look nonpolar...Ch. 2.2 - Make three-dimensional drawings of the following...Ch. 2.3 - Calculate formal charges for the nonhydrogen atoms...Ch. 2.3 - Organic phosphate groups occur commonly in...Ch. 2.6 - Which of the following pairs of structures...Ch. 2.6 - Draw the indicated number of resonance forms for...

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