To determine We need to determine the following: a) Total electrical energy used in Joules b) Average power use in watts c) Oil needed to generate the electricity consumed Explanation Given: 900 kilowatt-hours of energy are used in May 1 liter of oil releases 12 million joules of energy Formula used: Power in watts= Joules second Calculation: a) 1 kilowatt-hour=1000 x 3600 joule=3600000 joules 1050 kilowatt-hours=3600000 x 1050=3 .78 billion joules b) Time in seconds=31 x 24 x 3600=2678400 seconds Power in watts= 3 .78 billion Joules 2678400 second =1411 .29 watts c) 12 million joules of energy= 1 liter of oil 3 ...

Pearson eText for Using & Understanding Mathematics: A Quantitative Reasoning Approach -- Instant Access (Pearson+)

7th Edition

ISBN: 9780137553334

Author: Jeffrey Bennett, William Briggs

Publisher: PEARSON+

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Chapter 2.B, Problem 82E

To determine

We need to determine the following:

a) Total electrical energy used in Joules

b) Average power use in watts

c) Oil needed to generate the electricity consumed

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Chapter 2.B, Problem 81E

Chapter 2.B, Problem 83E

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Pearson eText for Using & Understanding Mathematics: A Quantitative Reasoning Approach -- Instant Access (Pearson+)

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