Explanation In order to obtain the double integral, integrate the inner integral first. ∫ 0 1 y sin x d y = sin x ∫ 0 1 y d y = sin x [ y 2 2 ] 0 1 = sin x [ ( 1 ) 2 2 − ( 0 ) 2 2 ] = sin x 2 Now, obtain the outer integral with the help of the result of inner integral as follows. ∫ 0 π 6 sin x 2 d x = 1 2 [ − cos x ] <

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Chapter 29.4, Problem 16E

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The value of the double integral ∫0π6∫01ysinxdydx.

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Chapter 29.4, Problem 15E

Chapter 29.4, Problem 17E

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Chapter 29 Solutions

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

Ch. 29.1 - Practice Exercise If f(x, y) = 4xy2 – 3x2y, find...Ch. 29.1 - Prob. 1E Ch. 29.1 - Prob. 2E Ch. 29.1 - Prob. 3E Ch. 29.1 - Prob. 4E Ch. 29.1 - Prob. 5E Ch. 29.1 - Prob. 6E Ch. 29.1 - Prob. 7E Ch. 29.1 - Prob. 8E Ch. 29.1 - Prob. 9E

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The value of the double integral ∫ 0 π 6 ∫ 0 1 y sin x d y d x .

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Chapter 29 Solutions