Explanation Given data: Rate of photon emission is 10 29 photons m 2 ⋅ s . Wavelength of the laser beam is 500 nm. Formula used: Write the expression for energy. E = h c λ (1) Here, E is the energy, h is the Planck’s constant with value 6.62 × 10 − 34 m 2 ⋅ kg s , c is the speed of the light 3 × 10 8 m s , and λ is the wavelength. Consider the expression for intensity. I = Rate of photon emission × Energy of each photon (2) Here, I is the intensity. Explanation: For energy of each photon, Each photon will use double the wavelength of 500 nm, so the wavelength of the photons is λ = 1000 nm Substitute 6.62 × 10 − 34 m 2 ⋅ kg s for h , 3 × 10 8 m s for c and 1000 × 10 − 9 m for λ in equation (2), E = ( 6.62 × 10 − 34 m 2 ⋅ kg s ) ( 3 × 10 8 m s ) 350 × 10 − 9 m = ( 1

Student Workbook for College Physics: A Strategic Approach Volume 1 (Chs. 1-16)

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ISBN: 9780321908865

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Chapter 29, Problem 75GP

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Minimum intensity of the laser beam during each pulse.

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Chapter 29, Problem 74GP

Chapter 29, Problem 76MSPP

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Three point-like charges are placed at the corners of a square as shown in the figure, 28.0 cm on each side. Find the minimum amount of work required by an external force to move the charge q1 to infinity. Let q1=-2.10 μC, q2=+2.40 μС, q3=+3.60 μC.

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Student Workbook for College Physics: A Strategic Approach Volume 1 (Chs. 1-16)

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