Explanation Given data: Wavelength is 121.6 nm. Formula used: Consider the expression of Kinetic energy. K = E 2 − E 1 (1) Here, E 2 is the energy of atom 2, and E 1 is the energy of atom 1. Consider the expression of Kinetic energy. K = 1 2 m v 2 (2) Here, m is the mass of photon, which has a standard value of 1.67 × 10 − 27 kg . v is the velocity. Work function equation E = h c λ (3) Here, h is the planks constant, which has a standard value as 6.63 × 10 − 34 J ⋅ s , c is the speed of light , which has a standard value as 3 × 10 8 m s , and λ is the wavelength. Explanation: Substitute equations (2) and (3) in equation (1), 1 2 m v 2 = h c λ 2 − h c λ 1 1 2 m v 2 = h c λ 2 − λ 1 Substitute 6.63 × 10 − 34 J ⋅ s for h , 3 × 10 8 m s for c , 1.67 × 10 − 27 kg for m , and 121.6 nm for λ 2 − λ 1 , 1 2 ( 1.67 × 10 − 27 kg ) × v 2 = ( 6.63 × 10 − 34 J ⋅ s ) ( 3 × 10 8 m s ) 121

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Chapter 29, Problem 64GP

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The speed of atom just before the collision.

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Chapter 29, Problem 63GP

Chapter 29, Problem 65GP

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