Explanation Given data: The current decay rate of the mallet is 1 16 times to that carbon -14 decay rate. Formula used: The expression to calculate the half life of a sample is, T = ln 2 λ Here, λ is the decay constant. Activity or decay rate expression for a sample is, A = − λ N 0 e − λ t Here, N 0 is the initial quantity and t is time after which the quantity is being measured. Explanation: Consider that the life time of a carbon − 14 is equal to 5730 years . Recall the expression for Activity or decay rate. A = − λ N 0 e − λ t To determine the decay at t = 0 , substitute 0 for t . A = − λ N 0 e − λ ( 0 ) = − λ N 0 So, consider that the above expression is for the condition, when the decay of a radioactive element just starts. The decay rate for mallet after any time t will be, A m a l l e t = − λ N 0 e − λ t The ratio of activity of mallet (now) to carbon -14 (initially) is given equal to ( 1 16 ) . So, A m a l l e t A = 1 16 Substitute − λ N 0 e − λ t for A m a l l e t and − λ N 0 for A . − λ N 0 e − λ t − λ N 0 = 1 16 Solve for t

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The radioactivity can be simply referred to as particle emission from nuclei due to the nuclear instability. There are different types of radiation such as alpha, beta and gamma radiation. Along with these there are different types of decay as well.

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Chapter 29, Problem 46P

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The age of a mallet, if the current decay rate is 116 times that of carbon -14 decay rate.

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Chapter 29, Problem 45P

Chapter 29, Problem 47P

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Ch. 29 - Prob. 1RQ Ch. 29 - Prob. 2RQ Ch. 29 - Prob. 3RQ Ch. 29 - Prob. 4RQ Ch. 29 - Prob. 5RQ Ch. 29 - Prob. 6RQ Ch. 29 - Prob. 7RQ Ch. 29 - Prob. 8RQ Ch. 29 - Review Question 29.9 Why are X-rays, gamma rays,...Ch. 29 - Prob. 1MCQ

Ch. 29 - Prob. 2MCQ Ch. 29 - Prob. 3MCQ Ch. 29 - Prob. 4MCQ Ch. 29 - Prob. 5MCQ Ch. 29 - Prob. 6MCQ Ch. 29 - Prob. 7MCQ Ch. 29 - Prob. 8MCQ Ch. 29 - Prob. 9MCQ Ch. 29 - Prob. 10MCQ Ch. 29 - Prob. 11CQ Ch. 29 - Prob. 12CQ Ch. 29 - Prob. 13CQ Ch. 29 - Prob. 14CQ Ch. 29 - How did Rutherford determine that radioactivity...Ch. 29 - Prob. 16CQ Ch. 29 - Prob. 17CQ Ch. 29 - Prob. 18CQ Ch. 29 - Prob. 19CQ Ch. 29 - Prob. 20CQ Ch. 29 - Prob. 21CQ Ch. 29 - Prob. 22CQ Ch. 29 - Prob. 1P Ch. 29 - Prob. 2P Ch. 29 - Prob. 3P Ch. 29 - Prob. 4P Ch. 29 - Prob. 6P Ch. 29 - Prob. 7P Ch. 29 - Prob. 8P Ch. 29 - Prob. 9P Ch. 29 - Prob. 10P Ch. 29 - Prob. 11P Ch. 29 - Prob. 12P Ch. 29 - Prob. 13P Ch. 29 - Prob. 14P Ch. 29 - Prob. 15P Ch. 29 - Prob. 16P Ch. 29 - Prob. 17P Ch. 29 - Prob. 18P Ch. 29 - Prob. 19P Ch. 29 - Prob. 20P Ch. 29 - Prob. 21P Ch. 29 - Prob. 22P Ch. 29 - 23. * Another Sun process A series of reactions...Ch. 29 - Prob. 24P Ch. 29 - Prob. 25P Ch. 29 - Prob. 27P Ch. 29 - Prob. 28P Ch. 29 - Prob. 29P Ch. 29 - Prob. 30P Ch. 29 - Prob. 31P Ch. 29 - Prob. 32P Ch. 29 - Prob. 33P Ch. 29 - Prob. 34P Ch. 29 - Prob. 35P Ch. 29 - Prob. 36P Ch. 29 - 37. * Cesium-137, a waste product of nuclear...Ch. 29 - Prob. 38P Ch. 29 - Prob. 39P Ch. 29 - Prob. 40P Ch. 29 - Prob. 41P Ch. 29 - Prob. 42P Ch. 29 - Prob. 43P Ch. 29 - Prob. 44P Ch. 29 - Prob. 45P Ch. 29 - Prob. 46P Ch. 29 - Prob. 47P Ch. 29 - Prob. 48P Ch. 29 - Prob. 49P Ch. 29 - Prob. 50P Ch. 29 - Prob. 52P Ch. 29 - Prob. 53P Ch. 29 - Prob. 54P Ch. 29 - Prob. 55P Ch. 29 - Prob. 56P Ch. 29 - Prob. 57GP Ch. 29 - Prob. 59GP Ch. 29 - Prob. 60GP Ch. 29 - Prob. 61GP Ch. 29 - Prob. 62GP Ch. 29 - Prob. 63GP Ch. 29 - Prob. 64GP Ch. 29 - Prob. 65GP Ch. 29 - Prob. 66GP Ch. 29 - Prob. 67GP Ch. 29 - Prob. 68GP Ch. 29 - Prob. 69GP Ch. 29 - Prob. 70GP Ch. 29 - Prob. 71GP Ch. 29 - Prob. 72RPP Ch. 29 - Prob. 73RPP Ch. 29 - Prob. 74RPP Ch. 29 - Prob. 75RPP Ch. 29 - Prob. 76RPP Ch. 29 - Prob. 77RPP Ch. 29 - Prob. 78RPP Ch. 29 - Prob. 79RPP Ch. 29 - Prob. 80RPP Ch. 29 - Prob. 81RPP

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