(a) Interpretation: The stereogenic center at C15 is to be labeled as R or S . Concept introduction: The stereochemistry of the compound is determined by prioritizing the groups attached to its stereogenic center. The groups are prioritized on the basis of atomic number of their atoms. The group that contain atom with higher atomic number is given higher priority. Complete the circle in decreasing order of priority from 1 → 2 → 3 . The configuration of the compound is R and S when circle rotates in clockwise and anticlockwise direction.

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Answer 1

Question

Chapter 29, Problem 25P

Interpretation Introduction

(a)

Interpretation: The stereogenic center at C15 is to be labeled as R or S.

Concept introduction: The stereochemistry of the compound is determined by prioritizing the groups attached to its stereogenic center. The groups are prioritized on the basis of atomic number of their atoms. The group that contain atom with higher atomic number is given higher priority. Complete the circle in decreasing order of priority from 1→2→3. The configuration of the compound is R and S when circle rotates in clockwise and anticlockwise direction.

Interpretation Introduction

(b)

Interpretation: The two isomeric products formed on reaction of A with Zn(BH4)2 is to be drawn.

Concept introduction: Zincborohydride is a metal hydride reagent. It is a mild reducing agent which reduces ketones to alcohol. Diastereomers of a compound have at least one stereogenic centre with same configuration and at least one with opposite configuration.

Interpretation Introduction

(c)

Interpretation: The reagent used to convert the A to the single stereoisomer X is to be predicted.

Concept introduction: The chiral oxazaborolidine catalysts are enantiomeric selective reducing reagent. The carbonyl group of ketones are reduced to form one stereoisomer in the enantiomeric excess.

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The following equations represent the formation of compound MX. What is the AH for the electron affinity of X (g)? X₂ (g) → 2X (g) M (s) → M (g) M (g) M (g) + e- AH = 60 kJ/mol AH = 22 kJ/mol X (g) + e-X (g) M* (g) +X (g) → MX (s) AH = 118 kJ/mol AH = ? AH = -190 kJ/mol AH = -100 kJ/mol a) -80 kJ b) -30 kJ c) -20 kJ d) 20 kJ e) 156 kJ

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Answer 2

Question

Chapter 29, Problem 25P

Interpretation Introduction

(a)

Interpretation: The stereogenic center at C15 is to be labeled as R or S.

Concept introduction: The stereochemistry of the compound is determined by prioritizing the groups attached to its stereogenic center. The groups are prioritized on the basis of atomic number of their atoms. The group that contain atom with higher atomic number is given higher priority. Complete the circle in decreasing order of priority from 1→2→3. The configuration of the compound is R and S when circle rotates in clockwise and anticlockwise direction.

Interpretation Introduction

(b)

Interpretation: The two isomeric products formed on reaction of A with Zn(BH4)2 is to be drawn.

Concept introduction: Zincborohydride is a metal hydride reagent. It is a mild reducing agent which reduces ketones to alcohol. Diastereomers of a compound have at least one stereogenic centre with same configuration and at least one with opposite configuration.

Interpretation Introduction

(c)

Interpretation: The reagent used to convert the A to the single stereoisomer X is to be predicted.

Concept introduction: The chiral oxazaborolidine catalysts are enantiomeric selective reducing reagent. The carbonyl group of ketones are reduced to form one stereoisomer in the enantiomeric excess.

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Answer 3

Question

Chapter 29, Problem 25P

Interpretation Introduction

(a)

Interpretation: The stereogenic center at C15 is to be labeled as R or S.

Concept introduction: The stereochemistry of the compound is determined by prioritizing the groups attached to its stereogenic center. The groups are prioritized on the basis of atomic number of their atoms. The group that contain atom with higher atomic number is given higher priority. Complete the circle in decreasing order of priority from 1→2→3. The configuration of the compound is R and S when circle rotates in clockwise and anticlockwise direction.

Interpretation Introduction

(b)

Interpretation: The two isomeric products formed on reaction of A with Zn(BH4)2 is to be drawn.

Concept introduction: Zincborohydride is a metal hydride reagent. It is a mild reducing agent which reduces ketones to alcohol. Diastereomers of a compound have at least one stereogenic centre with same configuration and at least one with opposite configuration.

Interpretation Introduction

(c)

Interpretation: The reagent used to convert the A to the single stereoisomer X is to be predicted.

Concept introduction: The chiral oxazaborolidine catalysts are enantiomeric selective reducing reagent. The carbonyl group of ketones are reduced to form one stereoisomer in the enantiomeric excess.

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Answer 4

Question

Chapter 29, Problem 25P

Interpretation Introduction

(a)

Interpretation: The stereogenic center at C15 is to be labeled as R or S.

Concept introduction: The stereochemistry of the compound is determined by prioritizing the groups attached to its stereogenic center. The groups are prioritized on the basis of atomic number of their atoms. The group that contain atom with higher atomic number is given higher priority. Complete the circle in decreasing order of priority from 1→2→3. The configuration of the compound is R and S when circle rotates in clockwise and anticlockwise direction.

Interpretation Introduction

(b)

Interpretation: The two isomeric products formed on reaction of A with Zn(BH4)2 is to be drawn.

Concept introduction: Zincborohydride is a metal hydride reagent. It is a mild reducing agent which reduces ketones to alcohol. Diastereomers of a compound have at least one stereogenic centre with same configuration and at least one with opposite configuration.

Interpretation Introduction

(c)

Interpretation: The reagent used to convert the A to the single stereoisomer X is to be predicted.

Concept introduction: The chiral oxazaborolidine catalysts are enantiomeric selective reducing reagent. The carbonyl group of ketones are reduced to form one stereoisomer in the enantiomeric excess.

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Answer 5

Chapter 29, Problem 25P

Interpretation Introduction

(a)

Interpretation: The stereogenic center at C15 is to be labeled as R or S.

Concept introduction: The stereochemistry of the compound is determined by prioritizing the groups attached to its stereogenic center. The groups are prioritized on the basis of atomic number of their atoms. The group that contain atom with higher atomic number is given higher priority. Complete the circle in decreasing order of priority from 1→2→3. The configuration of the compound is R and S when circle rotates in clockwise and anticlockwise direction.

Interpretation Introduction

(b)

Interpretation: The two isomeric products formed on reaction of A with Zn(BH4)2 is to be drawn.

Concept introduction: Zincborohydride is a metal hydride reagent. It is a mild reducing agent which reduces ketones to alcohol. Diastereomers of a compound have at least one stereogenic centre with same configuration and at least one with opposite configuration.

Interpretation Introduction

(c)

Interpretation: The reagent used to convert the A to the single stereoisomer X is to be predicted.

Concept introduction: The chiral oxazaborolidine catalysts are enantiomeric selective reducing reagent. The carbonyl group of ketones are reduced to form one stereoisomer in the enantiomeric excess.

Answer 6

Chapter 29, Problem 25P

Interpretation Introduction

(a)

Interpretation: The stereogenic center at C15 is to be labeled as R or S.

Concept introduction: The stereochemistry of the compound is determined by prioritizing the groups attached to its stereogenic center. The groups are prioritized on the basis of atomic number of their atoms. The group that contain atom with higher atomic number is given higher priority. Complete the circle in decreasing order of priority from 1→2→3. The configuration of the compound is R and S when circle rotates in clockwise and anticlockwise direction.

Answer 7

Chapter 29, Problem 25P

Interpretation Introduction

(a)

Interpretation: The stereogenic center at C15 is to be labeled as R or S.

Concept introduction: The stereochemistry of the compound is determined by prioritizing the groups attached to its stereogenic center. The groups are prioritized on the basis of atomic number of their atoms. The group that contain atom with higher atomic number is given higher priority. Complete the circle in decreasing order of priority from 1→2→3. The configuration of the compound is R and S when circle rotates in clockwise and anticlockwise direction.

Answer 8

Interpretation Introduction

(b)

Interpretation: The two isomeric products formed on reaction of A with Zn(BH4)2 is to be drawn.

Concept introduction: Zincborohydride is a metal hydride reagent. It is a mild reducing agent which reduces ketones to alcohol. Diastereomers of a compound have at least one stereogenic centre with same configuration and at least one with opposite configuration.

Answer 9

Interpretation Introduction

(b)

Interpretation: The two isomeric products formed on reaction of A with Zn(BH4)2 is to be drawn.

Concept introduction: Zincborohydride is a metal hydride reagent. It is a mild reducing agent which reduces ketones to alcohol. Diastereomers of a compound have at least one stereogenic centre with same configuration and at least one with opposite configuration.

Answer 10

Interpretation Introduction

(c)

Interpretation: The reagent used to convert the A to the single stereoisomer X is to be predicted.

Concept introduction: The chiral oxazaborolidine catalysts are enantiomeric selective reducing reagent. The carbonyl group of ketones are reduced to form one stereoisomer in the enantiomeric excess.

Answer 11

Interpretation Introduction

(c)

Interpretation: The reagent used to convert the A to the single stereoisomer X is to be predicted.

Concept introduction: The chiral oxazaborolidine catalysts are enantiomeric selective reducing reagent. The carbonyl group of ketones are reduced to form one stereoisomer in the enantiomeric excess.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 29.2 - Problem 31.1 One component of jojoba oil is a wax...Ch. 29.3 - Problem 31.2 How would you expect the melting...Ch. 29.3 - Problem 31.3 Draw the products formed when...Ch. 29.3 - Problem 31.4 The main fatty acid component of the...Ch. 29.3 - Prob. 5P Ch. 29.7 - Problem 31.10 Locate the isoprene units in each...Ch. 29.7 - Problem 31.11 Locate the isoprene units in...Ch. 29.7 - Problem 31.12 Write a stepwise mechanism for the...Ch. 29.7 - Prob. 14P Ch. 29.8 - Prob. 15P

Solution Summary: The author explains that the stereogenic center at C15 is labeled as R or S.

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Chapter 29 Solutions