Concept explainers
Introduction:
Reproductive innovation is a phenomenon that involves the introduction of new devices or methods in the process of reproduction during the process of evolution. These innovations are also called as the adaptations, which were acquired by the organisms according to the changes in the surrounding environment.
Answer to Problem 1TYK
Correct answer:
The ovary.
Explanation of Solution
Justification/ Explanation for the correct answer:
Option (d) is, ‘the ovary’. The ovary only gives protection to the seed. It does not take part in the formation of a seed, so, it was not a part of the reproductive innovation related to seed evolution. Hence, option (d) is correct.
Explanation for the incorrect answer:
Option (a) is, ‘reduced female gametophyte’. The special characteristic of the non-vascular plants was the large and dominant gametophytes. These gametophytes became smaller and the sporophytes became larger and dominant as the plants evolved according to the variations present in the environment. They play a very important role in reproductive innovation and result in seed evolution. So, it is an incorrect option.
Option (b) is, ‘heterospory’. It involves the production of two different-sized spores, and from different sexes by the sporophytes of land plants. It is thought that the early plants (all
Option (c) is “the ovule.” The ovule is an important structure of the plant, which is converted into the seed after fertilization. The gymnosperms had uncovered ovules on the scales of the cone. The gymnosperms had the ‘naked seeds’, that is, their seeds were not covered by the ovary. Then, as time passed, the seeds adapted to the surrounding environment and became covered with the help of ovary. The seeds of
Option (e) is “the integument.” It is a protective layer which surrounds the ovule. The gymnosperms have only one integument present around the ovule but, in the angiosperms, there are two integumentary coatings present as an adaptation toward the changing environment. The integument later converts into the seed coat which provides protection to the seed to survive in unfavorable conditions. So, it is an incorrect option.
Hence, options (a), (b), (c) and (e) are incorrect.
Therefore, it can be concluded that the female gametophytes, heterospory, the ovule, and the integument participated in the reproductive innovation related to seed evolution. The ovary does not have any role in reproductive innovation.
Want to see more full solutions like this?
Chapter 29 Solutions
Biology: The Dynamic Science
- What is the result of the acid-fast stain below: Stock Images by Getty Images by Getty Images by Getty Images by Getty Image Getty Images St Soy Getty Images by Getty Images by Getty Images Joy Getty encapsulated O endosporulating negative ○ positivearrow_forwardYou have a stock vial of diligence 75mg in 3ml and need to draw up a dose of 50mg for your patient.how many mls should you draw up to give this dosearrow_forwardYou are recquired to administer 150mg hydrocortisone intravenously,how many mls should you give?(stock =hydrocortisone 100mg in 2mls)arrow_forward
- If someone was working with a 50 MBq F-18 source, what would be the internal and external dose consequences?arrow_forwardWe will be starting a group project next week where you and your group will research and ultimately present on a current research article related to the biology of a pathogen that infects humans. The article could be about the pathogen itself, the disease process related to the pathogen, the immune response to the pathogen, vaccines or treatments that affect the pathogen, or other biology-related study about the pathogen. I recommend that you choose a pathogen that is currently interesting to researchers, so that you will be able to find plenty of articles about it. Avoid choosing a historical disease that no longer circulates. List 3 possible pathogens or diseases that you might want to do for your group project.arrow_forwardnot use ai pleasearrow_forward
- DNK dagi nukleotidlar va undan sintezlangan oqsildagi peptid boglar farqi 901 taga teng bo'lib undagi A jami H boglardan 6,5 marta kam bo'lsa DNK dagi jami H bog‘lar sonini topingarrow_forwardOne of the ways for a cell to generate ATP is through the oxidative phosphorylation. In oxidative phosphorylation 3 ATP are produced from every one NADH molecule. In respiration, every glucose molecule produces 10 NADH molecules. If a cell is growing on 5 glucose molecules, how much ATP can be produced using oxidative phosphorylation/aerobic respiration?arrow_forwardIf a cell is growing on 5 glucose molecules, how much ATP can be produced using oxidative phosphorylation/aerobic respiration?arrow_forward
- Concepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax CollegeBiology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage Learning
- Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage LearningBiology Today and Tomorrow without Physiology (Mi...BiologyISBN:9781305117396Author:Cecie Starr, Christine Evers, Lisa StarrPublisher:Cengage Learning