Physics Laboratory Experiments
8th Edition
ISBN: 9781285738567
Author: Jerry D. Wilson, Cecilia A. Hernández-Hall
Publisher: Cengage Learning
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Chapter 29, Problem 1Q
Judging on the basis of your experimental results, under what conditions are the charging times of different RC circuits the same?
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Chapter 29 Solutions
Physics Laboratory Experiments
Ch. 29 - Prob. 1ASACh. 29 - How is the time base of the horizontal...Ch. 29 - What is the significance of the RC time constant...Ch. 29 - Explain how the time constant of an RC circuit is...Ch. 29 - Judging on the basis of your experimental results,...Ch. 29 - In the form V = Vo(1 et/, the = RC in the...Ch. 29 - How could the value of an unknown capacitance be...
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- Make a VIRP table and complete it by measuring the voltage across each resistor and the power supply and measuring the current through each resistor and the total current and the total power coming out the power supply. Set your power supply to 24 V. Provide evidence that your table information is reasonable. Write down your reasoning and show your calculations. Figure B R1 = 100 Ω R2 = 90 Ω R3 = 105 Ωarrow_forwardDraw a circuit diagram for the case where both resistors (1000 ohms and 100 ohms) and an LED are connected in series and parallel. Taking the internal resistance of a single LED as 20 Ω, calculate the total current in the series and parallel circuits drawn. Then calculate the power, P (P = IV ), going through the LED in each of these cases. The battery is 3V.arrow_forwardWhat is the current read by the ammeter in the circuit below? Let R1 = 1 kiloohm, R2 = 2 kiloohm, R3 = 3 kiloohm, and the emf of the ideal source is 5 volts. All numerical answers should be in three significant figures. (Please fill in the blanks with the correct answers.)arrow_forward
- The combined electrical resistance R of two resistors R, and R. connected in parallel, is given by the equation below, where R, R₁, and are measured in ohms. R₁ and R, are increasing at rates of 0.5 and 2.0 ohms per second, respectively. 1 1 1 R₁+R₂ At what rate is R changing when R, 32 ohms and R₂ = 75 ohms? (Round your answer to three decimal places.) 0.573 xohm/sec Need Help? Read Watch Itarrow_forwardQUESTION 6 What is the current read by the ammeter in the circuit below? Let R1 = 1 kiloohm, R2 = 2 kiloohm, R3 = 3 kiloohm, and the emf of the ideal source is 5 volts. Input R1, R2, and R3 for resistors R1, R2, and R3 respectively. Input E for the emf E. Use context clues to figure out if you need to input a numerical value, variable, word, etc. All numerical answers should be in three significant figures. R1 R2 R3 A E First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current: | = Plugging in values, the current across the resistor R1 is equal to: (Please note that the current is in milliamperes) mAarrow_forwardIn the schematic below two batteries are in series and drive current through the circuit as shown. The first resistor has a voltage drop AV1= 2 V, the middle resistor has a resistance of R = 69 Q, and the last resistor has a voltage drop AV2 = 1.1 V. Given these parameters, what is the magnitude of current flowing through the circuit in milli-amps (mA)? Giver your answer to 3 significant figures. 3.0 V 4.5 V AV.arrow_forward
- In this experiment, you measured a resistor multiple times and obtained a mean resistance 33.7N. If the reference resistance value is 32N, what is the percent error of your measurement? (Please submit your answer without the % sign.)arrow_forwardOnly solve the q1arrow_forwardCAUTION: Ammeter will blow up if connected directly across the power source. therefore, it MUST BE CONNECTED TO A RESISTOR !!!!!!! Ruining an ammeter is EXPENSIVE!!! Data Tables Table 1. Resistor R₁ R₂ Table 2. 4.3 1₁ (A), from figure 2 0.084 Table 4. Digital Multimeter value [2] Table 3. Voltage across R₁(V) I(A) 51.5 0414 20.1 Voltage from power Current [A] supply [V] 5.980 0.116 5,980 0.298 Voltage across R₂(V) 1.67 1₁(A) 0.116 1₂ (A), from figure 3 0.084 VR1 + VR2 1₂ (A) 0.298 V R = // [22] % difference Voltage from power supply (V) 5.98 % error (1₁ + 1₂) (A) % error % differencearrow_forward
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