CAREY: ORGANIC CHEMISTRY
CAREY: ORGANIC CHEMISTRY
10th Edition
ISBN: 9781260364002
Author: VALUE EDITION
Publisher: MCG CUSTOM
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Chapter 28.11, Problem 10P
Interpretation Introduction

Interpretation: A lactam has to be explained. The structure of ε-caprolactum has to be drawn.

Concept introduction: Polymerization is the process in which the small molecules (monomer molecules) link together in a chemical reaction to form large chain that are called polymer. Polymer may contain one or more than one functional group in its structure. There are two types of polymerization, addition polymerization and condensation polymerization.

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Question 4 Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267 First-order, k = 0.210 hour 1 First-order, k = 0.0912 hour 1 O Second-order, k = 0.590 M1 hour 1 O Zero-order, k = 0.0770 M/hour O Zero-order, k = 0.4896 M/hour O Second-order, k = 1.93 M-1-hour 1 10 pts
Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267
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