College Physics (10th Edition)
10th Edition
ISBN: 9780321902788
Author: Hugh D. Young, Philip W. Adams, Raymond Joseph Chastain
Publisher: PEARSON
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Chapter 28, Problem 7CQ
To determine
The reason why photocurrent for large values of
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UV radiation having a wavelength of 120 nm falls on gold metal, to which electrons are bound by 4.82 eV. What is the maximum velocity of the ejected photoelectrons? No need to use relativistic formulas in this case, so you can just use the standard formula KE =12??2=12mv2.
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Chapter 28 Solutions
College Physics (10th Edition)
Ch. 28 - Prob. 1CQCh. 28 - Prob. 2CQCh. 28 - Prob. 3CQCh. 28 - Prob. 4CQCh. 28 - Prob. 5CQCh. 28 - Prob. 6CQCh. 28 - Prob. 7CQCh. 28 - Prob. 8CQCh. 28 - Prob. 9CQCh. 28 - Prob. 10CQ
Ch. 28 - Prob. 11CQCh. 28 - Prob. 12CQCh. 28 - Prob. 1MCPCh. 28 - Prob. 2MCPCh. 28 - Prob. 3MCPCh. 28 - Prob. 4MCPCh. 28 - Prob. 5MCPCh. 28 - Prob. 6MCPCh. 28 - Prob. 7MCPCh. 28 - Prob. 8MCPCh. 28 - Prob. 9MCPCh. 28 - Prob. 10MCPCh. 28 - Prob. 11MCPCh. 28 - Prob. 12MCPCh. 28 - Prob. 1PCh. 28 - Prob. 2PCh. 28 - Prob. 3PCh. 28 - Prob. 4PCh. 28 - Prob. 5PCh. 28 - Prob. 6PCh. 28 - Prob. 7PCh. 28 - Prob. 8PCh. 28 - Prob. 9PCh. 28 - Prob. 10PCh. 28 - Prob. 11PCh. 28 - Prob. 12PCh. 28 - Prob. 13PCh. 28 - Prob. 14PCh. 28 - Prob. 15PCh. 28 - Prob. 16PCh. 28 - Prob. 17PCh. 28 - Prob. 18PCh. 28 - Prob. 19PCh. 28 - Prob. 20PCh. 28 - Prob. 21PCh. 28 - Prob. 22PCh. 28 - Prob. 23PCh. 28 - Prob. 24PCh. 28 - Prob. 25PCh. 28 - Prob. 26PCh. 28 - Prob. 27PCh. 28 - Prob. 28PCh. 28 - Prob. 29PCh. 28 - Prob. 30PCh. 28 - Prob. 31PCh. 28 - Prob. 32PCh. 28 - Prob. 33PCh. 28 - Prob. 34PCh. 28 - Prob. 35PCh. 28 - Prob. 36PCh. 28 - Prob. 37PCh. 28 - Prob. 38PCh. 28 - Prob. 39PCh. 28 - Prob. 40PCh. 28 - Prob. 41PCh. 28 - Prob. 42PCh. 28 - Prob. 43PCh. 28 - Prob. 44PCh. 28 - Prob. 45PCh. 28 - Prob. 46PCh. 28 - Prob. 47PCh. 28 - Prob. 48PCh. 28 - Prob. 49PCh. 28 - Prob. 50GPCh. 28 - Prob. 51GPCh. 28 - Prob. 52GPCh. 28 - Prob. 53GPCh. 28 - Prob. 54GPCh. 28 - Prob. 55GPCh. 28 - Prob. 56GPCh. 28 - Prob. 57GPCh. 28 - Prob. 58GPCh. 28 - Prob. 59GPCh. 28 - Prob. 61GPCh. 28 - Prob. 62GPCh. 28 - Prob. 63GPCh. 28 - Prob. 64GPCh. 28 - Prob. 65GPCh. 28 - Prob. 66PPCh. 28 - Prob. 67PPCh. 28 - Prob. 68PPCh. 28 - Prob. 69PPCh. 28 - Prob. 70PPCh. 28 - Prob. 71PPCh. 28 - Prob. 72PPCh. 28 - Prob. 73PPCh. 28 - Prob. 74PP
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- 3.5. The threshold wavelength for photoelectric emission in Tungsten is 240 nm. What wavelength of light must be used in order that the emitted photoelectrons have a KE max of 1.2 eV.arrow_forwardMark the Correct Option.arrow_forwardUV radiation having a wavelength of 84 nm falls on gold metal, to which electrons are bound by 4.82 eV. What is the maximum velocity of the ejected photoelectrons? No need to use relativistic formulas in this case, so you can just use the standard formula KE =12mv2. The correct answer is 1.87E6 m/s how do I get that?arrow_forward
- A metal surface is illuminated with light of different wavelengths and the corresponding stopping potentials of the photoelectrons are shown in the Table below. A (A) 5581 61566731 V (V)1,05 0,86 0,67 Using the Table, determine the photoelectric threshold wavelength (in Å).arrow_forwardThe graph below shows the maximum kinetic energy of emitted photoelectrons as a function of the energy of the photons that are incident on a particular surface. From this graph, determine the following: a) the work function (in eV) 2) the threshold frequency (in Hz) Thank you for the help!arrow_forwardPotassium and gold cathodes are used in a photoelectric-effect experiment. For each cathode, find: The threshold frequency. The threshold wavelength. The maximum electron ejection speed if the light has a wavelength of 170 nm . The stopping potential if the wavelength is 170 nm . Throughout this problem, be sure to use 6.63×10−34J⋅s for Planck's constant. a) The maximum photoelectron ejection speed in meters per second for an electron ejected from potassium if the light has a wavelength of 170 nm. Express your answer in meters per second. b)The maximum photoelectron ejection speed in meters per second for an electron ejected from gold if the light has a wavelength of 170 nm . c)The stopping potential in volts for potassium if the wavelength is 170 nm. Express your answer in volts. d) The stopping potential in volts for gold if the wavelength is 170 nm. Express your answer in volts.arrow_forward
- A light of wavelength 352 nm with an intensity 2.00 W/m' is directed at a metallic surface. Only 0.60% of incident photons will produce photoelectrons. Calculate the number of photoelectrons emitted per second if the metallic surface has area of 2.00 cm². (a) 4.26x10 photoelectron/s (b) 7.09x10" photoelectron/s (c) 7.09x10 photoelectron/s (d) 4.26x10 photoelectron/sarrow_forwardIn a photoelectric experiment using a Potasium surface, you find a stopping potential of 0.57 V for a wavelength of 434 nm and a stopping potential of 2.30 V for a wavelength of 271 nm. Because this is an experiment, your value of Planck's constant will be slightly different from the official value. From these data find a) a value for Planck's constant h 8.81 x10-34 J . s b) the work function for Potasium 2.29 eV c) the cutoff wavelength for this metal 541.5 птarrow_forwardT3arrow_forward
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