Concept explainers
(a)
The measurement of a.

Answer to Problem 7A
The measurement of a is (332)′′.
Explanation of Solution
Given information:
The below figure represent the Metric steel Rule.
Figure-(1)
Write the expression for the measurement by the enlarged fractional rule.
M=F+T(132)′′ ........ (I)
Here, the measurement by the enlarged fractional rule is M, the total measurement of scale nearest of the point is F and the fractional measurement of scale nearest of the point is T.
Here, the total measurement of scale nearest of a is 0 and the fractional measurement of scale nearest of a is 3 as shown in Figure-(1).
Calculation:
Substitute 3 for T and 0 for F in Equation (I).
M=0+(3)(132)′′=(3)(132)′′=(332)′′
Conclusion:
The measurement of a is (332)′′.
(b)
The measurement of b.

Answer to Problem 7A
The measurement of b is (516)′′.
Explanation of Solution
Given information:
Here, the total measurement of scale nearest of b is 0 and the fractional measurement of scale nearest of b is 10 as shown in Figure-(1).
Calculation:
Substitute 0 for T and 10 for F in Equation (I).
M=(0)+(10)(132)′′=(10)(132)′′=(516)′′
Conclusion:
The measurement of b is (516)′′.
(c)
The measurement of c.

Answer to Problem 7A
The measurement of c is 0.5″.
Explanation of Solution
Given information:
Here, the total measurement of scale nearest of c is 0 and the fractional measurement of scale nearest of c is 16 as shown in Figure-(1).
Calculation:
Substitute 0 for T and 16 for F in Equation (I).
M=(0)+(16)(132)′′=(16)(132)′′=(12)′′=0.5″
Conclusion:
The measurement of c is 0.5′′.
(d)
The measurement of d.

Answer to Problem 7A
The measurement of d is (58)′′.
Explanation of Solution
Given information:
Here, the total measurement of scale nearest of d is 0.5″ and the fractional measurement of scale nearest of d is 4 as shown in Figure-(1).
Calculation:
Substitute 0.5″ for T and 4 for F in Equation (I).
M=0.5″+(4)(132)′′=(12)′′+(18)′′=(58)′′
Conclusion:
The measurement of d is (58)′′.
(e)
The measurement of e.

Answer to Problem 7A
The measurement of e is (34)′′.
Explanation of Solution
Given information:
Here, the total measurement of scale nearest of e is 0.5″ and the fractional measurement of scale nearest of e is 8 as shown in Figure-(1).
Calculation:
Substitute 0.5″ for T and 8 for F in Equation (I).
M=(0.5″)+(8)(132)′′=(12)′′+(14)′′=(34)′′
Conclusion:
The measurement of e is (34)′′.
(f)
The measurement of f.

Answer to Problem 7A
The measurement of f is (2932)′′.
Explanation of Solution
Given information:
Here, the total measurement of scale nearest of f is 0.5″ and the fractional measurement of scale nearest of f is 13 as shown in Figure-(1).
Calculation:
Substitute 0.5″ for T and 13 for F in Equation (I).
M=(0.5″)+(13)(132)′′=(12)′′+(1332)′′=(2932)′′
Conclusion:
The measurement of f is (2932)′′.
(g)
The measurement of g.

Answer to Problem 7A
The measurement of g is (3532)′′.
Explanation of Solution
Given information:
Here, the total measurement of scale nearest of g is 1″ and the fractional measurement of scale nearest of g is 3 as shown in Figure-(1).
Calculation:
Substitute 1″ for T and 3 for F in Equation (I).
M=(1″)+(3)(132)′′=(1″)+(332)′′=(3532)′′
Conclusion:
The measurement of g is (3532)′′.
(h)
The measurement of h.

Answer to Problem 7A
The measurement of h is (2116)′′.
Explanation of Solution
Given information:
Here, the total measurement of scale nearest of h is 1″ and the fractional measurement of scale nearest of h is 10 as shown in Figure-(1).
Calculation:
Substitute 1″ for T and 10 for F in Equation (I).
M=(1″)+(10)(132)′′=(1″)+(516)′′=(2116)′′
Conclusion:
The measurement of h is (2116)′′.
(i)
The measurement of i.

Answer to Problem 7A
The measurement of i is (564)′′.
Explanation of Solution
Given information:
Write the expression of measurement of the enlarged decimal rule.
M=F(132)′′+T(164)′′ ........ (II)
Here, the total measurement of scale nearest of i is 2 and the fractional measurement of scale nearest of i is 1 as shown in Figure-(1).
Calculation:
Substitute 2 for F and 1 for T in Equation (II).
M=2(132)′′+(164)′′=(16)′′+(164)′′=(564)′′
Conclusion:
The measurement of i is (564)′′.
(j)
The measurement of j.

Answer to Problem 7A
The measurement of j is (732)′′.
Explanation of Solution
Given information:
Here, the total measurement of scale nearest of j is 6 and the fractional measurement of scale nearest of c is 2 as shown in Figure-(1).
Calculation:
Substitute 6 for F and 2 for T in Equation (II).
M=(6)(132)′′+(2)(164)′′=(316)′′+(132)′′=(732)′′
Conclusion:
The measurement of j is (732)′′.
(k)
The measurement of k.

Answer to Problem 7A
The measurement of k is (38)′′.
Explanation of Solution
Given information:
Here, the total measurement of scale nearest of k is 0 and the fractional measurement of scale nearest of k is 12 as shown in Figure-(1).
Calculation:
Substitute 0 for T and 12 for F in Equation (I).
M=(0)+(12)(132)′′=(38)′′
Conclusion:
The measurement of k is (38)′′.
(l)
The measurement of l.

Answer to Problem 7A
The measurement of l is (3564)′′.
Explanation of Solution
Given information:
Here, the total measurement of scale nearest of l is 5 and the fractional measurement of scale nearest of l is 1 as shown in Figure-(1).
Write the expression for the enlarged decimal rule.
M=T1+F(132)′′+T(164)′′ ...... (III)
Here, the total measurement is T1.
Calculation:
Substitute (38)′′ for T1, 5 for F and 1 for T in Equation (II).
M=(38)′′+5(132)′′+(1)(164)′′=(38)′′+(532)′′+(164)′′=(3564)′′
Conclusion:
The measurement of l is (3564)′′.
(m)
The measurement of m.

Answer to Problem 7A
The measurement of m is (5164)′′.
Explanation of Solution
Given information:
Here, the total measurement of scale nearest of m is 24 and the fractional measurement of scale nearest of m is 3 as shown in Figure-(1).
Calculation:
Substitute 24 for F and 3 for T in Equation (I).
M=(24)(132)′′+(3)(164)′′=(5164)′′
Conclusion:
The measurement of m is (5164)′′.
(n)
The measurement of n.

Answer to Problem 7A
The measurement of n is (3132)′′.
Explanation of Solution
Given information:
Write the expression of measurement of the enlarged decimal rule.
M=T1−T(164)′′ ........ (IV)
Here, the total measurement is T1.
Here, the fractional measurement of scale nearest of n is 2 and the total measurement is 1″ as shown in Figure-(1).
Calculation:
Substitute 1″ for T1 and 2 for T in Equation (IV).
M=(1″)−2(164)′′=(1″)−(132)′′=(3132)′′
Conclusion:
The measurement of n is (3132)′′.
(o)
The measurement of o.

Answer to Problem 7A
The measurement of o is (11564)′′.
Explanation of Solution
Given information:
Here, the total measurement of scale nearest of m is 7, the fractional measurement of scale nearest of m is 1 and the total measurement is 1″ as shown in Figure-(1).
Calculation:
Substitute 1″ for T1, 7 for F and 1 for T in Equation (III).
M=(1″)+(7)(132)′′+(1)(164)′′=(1″)+(732)′′+(164)′′=(11564)′′
Conclusion:
The measurement of o is (11564)′′.
(o)
The measurement of p.

Answer to Problem 7A
The measurement of p is (12964)′′.
Explanation of Solution
Given information:
Here, the total measurement of scale nearest of m is 4, the fractional measurement of scale nearest of m is 1 and the total measurement is (2116)′′ as shown in Figure-(1).
Calculation:
Substitute (2116)′′ for T1, 4 for F and 1 for F in Equation (IV).
M=(2116)′′+(4)(132)′′+(1)(164)′′=(2116)′′+(18)′′+(164)′′=(2964)′′
Conclusion:
The measurement of p is (12964)′′.
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Chapter 28 Solutions
EBK MATHEMATICS FOR MACHINE TECHNOLOGY
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