Explanation 1) Concept: By using the formula for magnetic force acting on a moving charged particle, we can find the magnetic field B. 2) Formula: Magnetic force, F B → = q v → × B → 3) Given: i) Charge on the particle q = 2.0 C ii) Velocity of the particle v → = ( 2.0 i ^ + 4.0 j ^ + 6.0 k ^ ) m s 2 iii) Force acting on the particle F B → = ( 4.0 i ^ - 20 j ^ + 12 k ^ ) N 4) Calculations: a) To find the magnetic field, we use the formula for magnetic force in terms of velocity and magnetic field. Let the magnetic field vector be B → = ( B x i ^ + B y j ^ + B z k ^ ) T As it is given that x and y components of magnetic field are same, B x = B y B → = ( B x i ^ + B x j ^ + B z k ^ ) T We have F B → = q v → × B → Therefore, we can write 4.0 i ^ - 20 j ^ + 12 k ^ = 2 × i j k 2 4 6 B x B x B z By solving the matrix, 1 2 4

Fundamentals of Physics Extended 10e Binder Ready Version + WileyPLUS Registration Card

10th Edition

ISBN: 9781118732090

Author: David Halliday

Publisher: Wiley (WileyPLUS Products)

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Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.

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Chapter 28, Problem 74P

To determine

To find:

Magnetic field B→

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Chapter 28, Problem 73P

Chapter 28, Problem 75P

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Chapter 28 Solutions

Fundamentals of Physics Extended 10e Binder Ready Version + WileyPLUS Registration Card

Ch. 28 - Prob. 1Q Ch. 28 - Prob. 2Q Ch. 28 - Prob. 3Q Ch. 28 - Prob. 4Q Ch. 28 - In Module 28-2, we discussed a charged particle...Ch. 28 - Figure 28-26 shows crossed uniform electic and...Ch. 28 - Figure 28-27 shows the path of an electron that...Ch. 28 - Figure 28-28 shows the path of an electron in a...Ch. 28 - a In Checkpoint 5, if the dipole moment is rotated...Ch. 28 - Particle round about. Figure 28-29 shows 11 paths...

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