Explanation 1) Concept: We replace the loop of arbitrary shape with number of adjacent long, thin, approximately rectangular loops such that we can assume that the distribution of the current is not altered. Then we can prove the relation using the integration method. 2) Formulae: τ = N i A B s i n θ 3) Given: i)Figure 28.19 of rectangular loop ii) The equation for torque acting on the current loop as τ = N i A B s i n θ 4) Calculations: Let us replace the current loop of arbitrary shape with an assembly of thin, adjacent, and small rectangular loops such as to cover the same area enclosed by the original loop. We can assume that each rectangular loop carries the same current ‘i’ as that flowing through the original loop

Fundamentals of Physics Extended 10E WileyPlus 5 Student Package

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ISBN: 9781118441497

Author: Halliday

Publisher: John Wiley & Sons Inc (US)

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Chapter 28, Problem 53P

To determine

To find:

To prove that the relation τ=NiABsinθ holds for any closed loop of arbitrary shape.

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Chapter 28, Problem 52P

Chapter 28, Problem 54P

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Chapter 28 Solutions

Fundamentals of Physics Extended 10E WileyPlus 5 Student Package

Ch. 28 - Prob. 1Q Ch. 28 - Prob. 2Q Ch. 28 - Prob. 3Q Ch. 28 - Prob. 4Q Ch. 28 - In Module 28-2, we discussed a charged particle...Ch. 28 - Figure 28-26 shows crossed uniform electic and...Ch. 28 - Figure 28-27 shows the path of an electron that...Ch. 28 - Figure 28-28 shows the path of an electron in a...Ch. 28 - a In Checkpoint 5, if the dipole moment is rotated...Ch. 28 - Particle round about. Figure 28-29 shows 11 paths...

Knowledge Booster

To prove that the relation τ = N i A B s i n θ holds for any closed loop of arbitrary shape.

Solution Summary: The author explains how the equation tau =NiABsintheta can hold for any closed loop of arbitrary shape.

To find:

To prove that the relation τ=NiABsinθ holds for any closed loop of arbitrary shape.

Want to see the full answer?

Chapter 28 Solutions

To prove that the relation τ = N i A B s i n θ holds for any closed loop of arbitrary shape.

Solution Summary: The author explains how the equation tau =NiABsintheta can hold for any closed loop of arbitrary shape.

To find: To prove that the relation τ=NiABsinθ holds for any closed loop of arbitrary shape.

Want to see the full answer?

Chapter 28 Solutions

To find:

To prove that the relation τ=NiABsinθ holds for any closed loop of arbitrary shape.