(a) Explanation Given Info: Current in the wire ( I ) is 13.0 A , speed of electron ( v ) is 250 km / s and distance of electron from the wire ( r ) is 2.00 cm . Formula to determine the magnetic field in the wire, B = μ 0 I 2 π r (I) μ 0 is the magnetic constant, r is the distance of electron from the wire, I is the current in the wire. Formula to determine the force on a moving charge, F = B q v sin ϕ (II) B is the magnetic field of the wire due to the current flow, q is the charge, v is the speed of the electron, ϕ is the angle between magnetic field and motion of electron. Substitute μ 0 I 2 π r for B in equation (II). F = q v μ 0 I sin ϕ 2 π r (III) Formula to determine the initial acceleration of electron, a = F m (IV) F is the force, m is the mass of the electron. Substitute q v μ 0 I sin ϕ 2 π r for F in equation (IV) to find a . a = ( ( q v μ 0 I sin ϕ 2 π r ) m ) = q v μ 0 I sin ϕ 2 π r m (V) The magnetic field circles the wire. When the electron is fired parallel to the wire the velocity of electron will be at right angle. Therefore ϕ = 90 ° (b) To determine The magnitude and direction electric field. (c) To determine Whether to include the effects of gravity.

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ISBN: 9781323575208

Author: YOUNG

Publisher: PEARSON C

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Chapter 28, Problem 28.59P

(a)

To determine

The magnitude and direction of electron initial acceleration.

(b)

To determine

The magnitude and direction electric field.

(c)

To determine

Whether to include the effects of gravity.

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Chapter 28, Problem 28.58P

Chapter 28, Problem 28.60P

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The magnitude and direction of electron initial acceleration.

Solution Summary: The author explains how to determine the magnitude and direction of electron initial acceleration.

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The magnitude and direction of electron initial acceleration.

The magnitude and direction electric field.

Whether to include the effects of gravity.

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Chapter 28 Solutions