Explanation Given: The function f ( θ ) = tan 3 θ − 8 tan 2 θ + 17 tan θ − 8 The function has a root in the interval [0.5,0.6] Key concepts applied: The Bisection method is a method used to obtain a rough approximation to a solution of a given function. It is based on the intermediate value theorem for continuous functions. The bisection method is an iterative process, in which roots of a given equation are identified through bisection of a known interval that contains a root and then selecting a subinterval in which a root must lie for further processing. Calculation: The steps of bisection can be carried out as follows, Description f ( θ ) = tan 3 θ − 8 tan 2 θ + 17 tan θ − 8 Step 1: We know that f ( θ ) = tan 3 θ − 8 tan 2 θ + 17 tan θ − 8 has a zero in [0.5,0.6], which is an interval of length 0.1. Bisect this interval to create two new sub-intervals [0.5,0.55] and [0.55,0.6] of length 0.05. Find in which of these intervals does f ( θ ) have a root. Interval : [0.5,0.55] f ( 0.5 ) = tan 3 ( 0.5 ) − 8 tan 2 ( 0.5 ) + 17 tan ( 0.5 ) − 8 = ( 0.546 ) 3 − 8 ( 0.546 ) 2 + 17 ( 0.546 ) − 8 = 0.163 − 2.385 + 9.282 − 8 = − 0.94 < 0 f ( 0.55 ) = tan 3 ( 0.55 ) − 8 tan 2 ( 0.55 ) + 17 tan ( 0.55 ) − 8 = ( 0.613 ) 3 − 8 ( 0.613 ) 2 + 17 ( 0.613 ) − 8 = 0.23 − 3.008 + 10.421 − 8 = − 0.357 < 0 Since both values are negative, we cannot infer from IVT that there is a root for the function in the interval [0.5,0.55]. Interval : [0.55,0.6] f ( 0.55 ) = tan 3 ( 0.55 ) − 8 tan 2 ( 0.55 ) + 17 tan ( 0.55 ) − 8 = ( 0.613 ) 3 − 8 ( 0.613 ) 2 + 17 ( 0.613 ) − 8 = 0.23 − 3.008 + 10.421 − 8 = − 0.357 < 0 f ( 0.6 ) = tan 3 ( 0.6 ) − 8 tan 2 ( 0.6 ) + 17 tan ( 0.6 ) − 8 = ( 0.684 ) 3 − 8 ( 0.684 ) 2 + 17 ( 0.684 ) − 8 = 0.32 − 3.743 + 11

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

See similar textbooks

Concept explainers

Roots

Videos

Question

Chapter 2.8, Problem 24E

To determine

An interval of length 0.025 containing the root of the given function found in the given interval by applying the Bisection method twice.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 2.8, Problem 23E

Chapter 2.8, Problem 25E

Students have asked these similar questions

Find, correct to the nearest degree, the three angles of the triangle with vertices A(1, 0, −1), B(2, −5, 0),and C(1, 3, 4).

A line (L1) is perpendicular on the line (L2: 5X - BY +19-0) and intercept it at a point (-5, 2). Find 1- Value of B ? 2- Equation of (L1)

1 Written problems 1. Solve x' 0 1 -1 0 ] x +

Chapter 2 Solutions

Calculus - Standalone book

Ch. 2.1 - Prob. 1PQ Ch. 2.1 - Prob. 2PQ Ch. 2.1 - Prob. 3PQ Ch. 2.1 - Prob. 4PQ Ch. 2.1 - Prob. 5PQ Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E

Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.2 - Prob. 1PQ Ch. 2.2 - Prob. 2PQ Ch. 2.2 - Prob. 3PQ Ch. 2.2 - Prob. 4PQ Ch. 2.2 - Prob. 5PQ Ch. 2.2 - Prob. 6PQ Ch. 2.2 - Prob. 7PQ Ch. 2.2 - Prob. 1E Ch. 2.2 - Prob. 2E Ch. 2.2 - Prob. 3E Ch. 2.2 - Prob. 4E Ch. 2.2 - Prob. 5E Ch. 2.2 - Prob. 6E Ch. 2.2 - Prob. 7E Ch. 2.2 - Prob. 8E Ch. 2.2 - Prob. 9E Ch. 2.2 - Prob. 10E Ch. 2.2 - Prob. 11E Ch. 2.2 - Prob. 12E Ch. 2.2 - Prob. 13E Ch. 2.2 - Prob. 14E Ch. 2.2 - Prob. 15E Ch. 2.2 - Prob. 16E Ch. 2.2 - Prob. 17E Ch. 2.2 - Prob. 18E Ch. 2.2 - Prob. 19E Ch. 2.2 - Prob. 20E Ch. 2.2 - Prob. 21E Ch. 2.2 - Prob. 22E Ch. 2.2 - Prob. 23E Ch. 2.2 - Prob. 24E Ch. 2.2 - Prob. 25E Ch. 2.2 - Prob. 26E Ch. 2.2 - Prob. 27E Ch. 2.2 - Prob. 28E Ch. 2.2 - Prob. 29E Ch. 2.2 - Prob. 30E Ch. 2.2 - Prob. 31E Ch. 2.2 - Prob. 32E Ch. 2.2 - Prob. 33E Ch. 2.2 - Prob. 34E Ch. 2.2 - Prob. 35E Ch. 2.2 - Prob. 36E Ch. 2.2 - Prob. 37E Ch. 2.2 - Prob. 38E Ch. 2.2 - Prob. 39E Ch. 2.2 - Prob. 40E Ch. 2.2 - Prob. 41E Ch. 2.2 - Prob. 42E Ch. 2.2 - Prob. 43E Ch. 2.2 - Prob. 44E Ch. 2.2 - Prob. 45E Ch. 2.2 - Prob. 46E Ch. 2.2 - Prob. 47E Ch. 2.2 - Prob. 48E Ch. 2.2 - Prob. 49E Ch. 2.2 - Prob. 50E Ch. 2.2 - Prob. 51E Ch. 2.2 - Prob. 52E Ch. 2.2 - Prob. 53E Ch. 2.2 - Prob. 54E Ch. 2.2 - Prob. 55E Ch. 2.2 - Prob. 56E Ch. 2.2 - Prob. 57E Ch. 2.2 - Prob. 58E Ch. 2.2 - Prob. 59E Ch. 2.2 - Prob. 60E Ch. 2.2 - Prob. 61E Ch. 2.2 - Prob. 62E Ch. 2.2 - Prob. 63E Ch. 2.2 - Prob. 64E Ch. 2.2 - Prob. 65E Ch. 2.2 - Prob. 66E Ch. 2.2 - Prob. 67E Ch. 2.2 - Prob. 68E Ch. 2.2 - Prob. 69E Ch. 2.2 - Prob. 70E Ch. 2.3 - Prob. 1PQ Ch. 2.3 - Prob. 2PQ Ch. 2.3 - Prob. 3PQ Ch. 2.3 - Prob. 1E Ch. 2.3 - Prob. 2E Ch. 2.3 - Prob. 3E Ch. 2.3 - Prob. 4E Ch. 2.3 - Prob. 5E Ch. 2.3 - Prob. 6E Ch. 2.3 - Prob. 7E Ch. 2.3 - Prob. 8E Ch. 2.3 - Prob. 9E Ch. 2.3 - Prob. 10E Ch. 2.3 - Prob. 11E Ch. 2.3 - Prob. 12E Ch. 2.3 - Prob. 13E Ch. 2.3 - Prob. 14E Ch. 2.3 - Prob. 15E Ch. 2.3 - Prob. 16E Ch. 2.3 - Prob. 17E Ch. 2.3 - Prob. 18E Ch. 2.3 - Prob. 19E Ch. 2.3 - Prob. 20E Ch. 2.3 - Prob. 21E Ch. 2.3 - Prob. 22E Ch. 2.3 - Prob. 23E Ch. 2.3 - Prob. 24E Ch. 2.3 - Prob. 25E Ch. 2.3 - Prob. 26E Ch. 2.3 - Prob. 27E Ch. 2.3 - Prob. 28E Ch. 2.3 - Prob. 29E Ch. 2.3 - Prob. 30E Ch. 2.3 - Prob. 31E Ch. 2.3 - Prob. 32E Ch. 2.3 - Prob. 33E Ch. 2.3 - Prob. 34E Ch. 2.3 - Prob. 35E Ch. 2.3 - Prob. 36E Ch. 2.3 - Prob. 37E Ch. 2.3 - Prob. 38E Ch. 2.3 - Prob. 39E Ch. 2.3 - Prob. 40E Ch. 2.3 - Prob. 41E Ch. 2.3 - Prob. 42E Ch. 2.4 - Prob. 1PQ Ch. 2.4 - Prob. 2PQ Ch. 2.4 - Prob. 3PQ Ch. 2.4 - Prob. 4PQ Ch. 2.4 - Prob. 5PQ Ch. 2.4 - Prob. 1E Ch. 2.4 - Prob. 2E Ch. 2.4 - Prob. 3E Ch. 2.4 - Prob. 4E Ch. 2.4 - Prob. 5E Ch. 2.4 - Prob. 6E Ch. 2.4 - Prob. 7E Ch. 2.4 - Prob. 8E Ch. 2.4 - Prob. 9E Ch. 2.4 - Prob. 10E Ch. 2.4 - Prob. 11E Ch. 2.4 - Prob. 12E Ch. 2.4 - Prob. 13E Ch. 2.4 - Prob. 14E Ch. 2.4 - Prob. 15E Ch. 2.4 - Prob. 16E Ch. 2.4 - Prob. 17E Ch. 2.4 - Prob. 18E Ch. 2.4 - Prob. 19E Ch. 2.4 - Prob. 20E Ch. 2.4 - Prob. 21E Ch. 2.4 - Prob. 22E Ch. 2.4 - Prob. 23E Ch. 2.4 - Prob. 24E Ch. 2.4 - Prob. 25E Ch. 2.4 - Prob. 26E Ch. 2.4 - Prob. 27E Ch. 2.4 - Prob. 28E Ch. 2.4 - Prob. 29E Ch. 2.4 - Prob. 30E Ch. 2.4 - Prob. 31E Ch. 2.4 - Prob. 32E Ch. 2.4 - Prob. 33E Ch. 2.4 - Prob. 34E Ch. 2.4 - Prob. 35E Ch. 2.4 - Prob. 36E Ch. 2.4 - Prob. 37E Ch. 2.4 - Prob. 38E Ch. 2.4 - Prob. 39E Ch. 2.4 - Prob. 40E Ch. 2.4 - Prob. 41E Ch. 2.4 - Prob. 42E Ch. 2.4 - Prob. 43E Ch. 2.4 - Prob. 44E Ch. 2.4 - Prob. 45E Ch. 2.4 - Prob. 46E Ch. 2.4 - Prob. 47E Ch. 2.4 - Prob. 48E Ch. 2.4 - Prob. 49E Ch. 2.4 - Prob. 50E Ch. 2.4 - Prob. 51E Ch. 2.4 - Prob. 52E Ch. 2.4 - Prob. 53E Ch. 2.4 - Prob. 54E Ch. 2.4 - Prob. 55E Ch. 2.4 - Prob. 56E Ch. 2.4 - Prob. 57E Ch. 2.4 - Prob. 58E Ch. 2.4 - Prob. 59E Ch. 2.4 - Prob. 60E Ch. 2.4 - Prob. 61E Ch. 2.4 - Prob. 62E Ch. 2.4 - Prob. 63E Ch. 2.4 - Prob. 64E Ch. 2.4 - Prob. 65E Ch. 2.4 - Prob. 66E Ch. 2.4 - Prob. 67E Ch. 2.4 - Prob. 68E Ch. 2.4 - Prob. 69E Ch. 2.4 - Prob. 70E Ch. 2.4 - Prob. 71E Ch. 2.4 - Prob. 72E Ch. 2.4 - Prob. 73E Ch. 2.4 - Prob. 74E Ch. 2.4 - Prob. 75E Ch. 2.4 - Prob. 76E Ch. 2.4 - Prob. 77E Ch. 2.4 - Prob. 78E Ch. 2.4 - Prob. 79E Ch. 2.4 - Prob. 80E Ch. 2.4 - Prob. 81E Ch. 2.4 - Prob. 82E Ch. 2.4 - Prob. 83E Ch. 2.4 - Prob. 84E Ch. 2.4 - Prob. 85E Ch. 2.4 - Prob. 86E Ch. 2.4 - Prob. 87E Ch. 2.4 - Prob. 88E Ch. 2.4 - Prob. 89E Ch. 2.5 - Prob. 1PQ Ch. 2.5 - Prob. 2PQ Ch. 2.5 - Prob. 3PQ Ch. 2.5 - Prob. 1E Ch. 2.5 - Prob. 2E Ch. 2.5 - Prob. 3E Ch. 2.5 - Prob. 4E Ch. 2.5 - Prob. 5E Ch. 2.5 - Prob. 6E Ch. 2.5 - Prob. 7E Ch. 2.5 - Prob. 8E Ch. 2.5 - Prob. 9E Ch. 2.5 - Prob. 10E Ch. 2.5 - Prob. 11E Ch. 2.5 - Prob. 12E Ch. 2.5 - Prob. 13E Ch. 2.5 - Prob. 14E Ch. 2.5 - Prob. 15E Ch. 2.5 - Prob. 16E Ch. 2.5 - Prob. 17E Ch. 2.5 - Prob. 18E Ch. 2.5 - Prob. 19E Ch. 2.5 - Prob. 20E Ch. 2.5 - Prob. 21E Ch. 2.5 - Prob. 22E Ch. 2.5 - Prob. 23E Ch. 2.5 - Prob. 24E Ch. 2.5 - Prob. 25E Ch. 2.5 - Prob. 26E Ch. 2.5 - Prob. 27E Ch. 2.5 - Prob. 28E Ch. 2.5 - Prob. 29E Ch. 2.5 - Prob. 30E Ch. 2.5 - Prob. 31E Ch. 2.5 - Prob. 32E Ch. 2.5 - Prob. 33E Ch. 2.5 - Prob. 34E Ch. 2.5 - Prob. 35E Ch. 2.5 - Prob. 36E Ch. 2.5 - Prob. 37E Ch. 2.5 - Prob. 38E Ch. 2.5 - Prob. 39E Ch. 2.5 - Prob. 40E Ch. 2.5 - Prob. 41E Ch. 2.5 - Prob. 42E Ch. 2.5 - Prob. 43E Ch. 2.5 - Prob. 44E Ch. 2.5 - Prob. 45E Ch. 2.5 - Prob. 46E Ch. 2.5 - Prob. 47E Ch. 2.5 - Prob. 48E Ch. 2.5 - Prob. 49E Ch. 2.5 - Prob. 50E Ch. 2.5 - Prob. 51E Ch. 2.5 - Prob. 52E Ch. 2.5 - Prob. 53E Ch. 2.5 - Prob. 54E Ch. 2.5 - Prob. 55E Ch. 2.5 - Prob. 56E Ch. 2.5 - Prob. 57E Ch. 2.5 - Prob. 58E Ch. 2.5 - Prob. 59E Ch. 2.6 - Prob. 1PQ Ch. 2.6 - Prob. 2PQ Ch. 2.6 - Prob. 3PQ Ch. 2.6 - Prob. 1E Ch. 2.6 - Prob. 2E Ch. 2.6 - Prob. 3E Ch. 2.6 - Prob. 4E Ch. 2.6 - Prob. 5E Ch. 2.6 - Prob. 6E Ch. 2.6 - Prob. 7E Ch. 2.6 - Prob. 8E Ch. 2.6 - Prob. 9E Ch. 2.6 - Prob. 10E Ch. 2.6 - Prob. 11E Ch. 2.6 - Prob. 12E Ch. 2.6 - Prob. 13E Ch. 2.6 - Prob. 14E Ch. 2.6 - Prob. 15E Ch. 2.6 - Prob. 16E Ch. 2.6 - Prob. 17E Ch. 2.6 - Prob. 18E Ch. 2.6 - Prob. 19E Ch. 2.6 - Prob. 20E Ch. 2.6 - Prob. 21E Ch. 2.6 - Prob. 22E Ch. 2.6 - Prob. 23E Ch. 2.6 - Prob. 24E Ch. 2.6 - Prob. 25E Ch. 2.6 - Prob. 26E Ch. 2.6 - Prob. 27E Ch. 2.6 - Prob. 28E Ch. 2.6 - Prob. 29E Ch. 2.6 - Prob. 30E Ch. 2.6 - Prob. 31E Ch. 2.6 - Prob. 32E Ch. 2.6 - Prob. 33E Ch. 2.6 - Prob. 34E Ch. 2.6 - Prob. 35E Ch. 2.6 - Prob. 36E Ch. 2.6 - Prob. 37E Ch. 2.6 - Prob. 38E Ch. 2.6 - Prob. 39E Ch. 2.6 - Prob. 40E Ch. 2.6 - Prob. 41E Ch. 2.6 - Prob. 42E Ch. 2.6 - Prob. 43E Ch. 2.6 - Prob. 44E Ch. 2.6 - Prob. 45E Ch. 2.6 - Prob. 46E Ch. 2.6 - Prob. 47E Ch. 2.6 - Prob. 48E Ch. 2.6 - Prob. 49E Ch. 2.6 - Prob. 50E Ch. 2.6 - Prob. 51E Ch. 2.6 - Prob. 52E Ch. 2.6 - Prob. 53E Ch. 2.6 - Prob. 54E Ch. 2.6 - Prob. 55E Ch. 2.6 - Prob. 56E Ch. 2.6 - Prob. 57E Ch. 2.6 - Prob. 58E Ch. 2.6 - Prob. 59E Ch. 2.7 - Prob. 1PQ Ch. 2.7 - Prob. 2PQ Ch. 2.7 - Prob. 3PQ Ch. 2.7 - Prob. 4PQ Ch. 2.7 - Prob. 5PQ Ch. 2.7 - Prob. 6PQ Ch. 2.7 - Prob. 1E Ch. 2.7 - Prob. 2E Ch. 2.7 - Prob. 3E Ch. 2.7 - Prob. 4E Ch. 2.7 - Prob. 5E Ch. 2.7 - Prob. 6E Ch. 2.7 - Prob. 7E Ch. 2.7 - Prob. 8E Ch. 2.7 - Prob. 9E Ch. 2.7 - Prob. 10E Ch. 2.7 - Prob. 11E Ch. 2.7 - Prob. 12E Ch. 2.7 - Prob. 13E Ch. 2.7 - Prob. 14E Ch. 2.7 - Prob. 15E Ch. 2.7 - Prob. 16E Ch. 2.7 - Prob. 17E Ch. 2.7 - Prob. 18E Ch. 2.7 - Prob. 19E Ch. 2.7 - Prob. 20E Ch. 2.7 - Prob. 21E Ch. 2.7 - Prob. 22E Ch. 2.7 - Prob. 23E Ch. 2.7 - Prob. 24E Ch. 2.7 - Prob. 25E Ch. 2.7 - Prob. 26E Ch. 2.7 - Prob. 27E Ch. 2.7 - Prob. 28E Ch. 2.7 - Prob. 29E Ch. 2.7 - Prob. 30E Ch. 2.7 - Prob. 31E Ch. 2.7 - Prob. 32E Ch. 2.7 - Prob. 33E Ch. 2.7 - Prob. 34E Ch. 2.7 - Prob. 35E Ch. 2.7 - Prob. 36E Ch. 2.7 - Prob. 37E Ch. 2.7 - Prob. 38E Ch. 2.7 - Prob. 39E Ch. 2.7 - Prob. 40E Ch. 2.7 - Prob. 41E Ch. 2.7 - Prob. 42E Ch. 2.7 - Prob. 43E Ch. 2.7 - Prob. 44E Ch. 2.7 - Prob. 45E Ch. 2.8 - Prob. 1PQ Ch. 2.8 - Prob. 2PQ Ch. 2.8 - Prob. 3PQ Ch. 2.8 - Prob. 4PQ Ch. 2.8 - Prob. 5PQ Ch. 2.8 - Prob. 1E Ch. 2.8 - Prob. 2E Ch. 2.8 - Prob. 3E Ch. 2.8 - Prob. 4E Ch. 2.8 - Prob. 5E Ch. 2.8 - Prob. 6E Ch. 2.8 - Prob. 7E Ch. 2.8 - Prob. 8E Ch. 2.8 - Prob. 9E Ch. 2.8 - Prob. 10E Ch. 2.8 - Prob. 11E Ch. 2.8 - Prob. 12E Ch. 2.8 - Prob. 13E Ch. 2.8 - Prob. 14E Ch. 2.8 - Prob. 15E Ch. 2.8 - Prob. 16E Ch. 2.8 - Prob. 17E Ch. 2.8 - Prob. 18E Ch. 2.8 - Prob. 19E Ch. 2.8 - Prob. 20E Ch. 2.8 - Prob. 21E Ch. 2.8 - Prob. 22E Ch. 2.8 - Prob. 23E Ch. 2.8 - Prob. 24E Ch. 2.8 - Prob. 25E Ch. 2.8 - Prob. 26E Ch. 2.8 - Prob. 27E Ch. 2.8 - Prob. 28E Ch. 2.8 - Prob. 29E Ch. 2.8 - Prob. 30E Ch. 2.8 - Prob. 31E Ch. 2.8 - Prob. 32E Ch. 2.8 - Prob. 33E Ch. 2.8 - Prob. 34E Ch. 2.8 - Prob. 35E Ch. 2.9 - Prob. 1PQ Ch. 2.9 - Prob. 2PQ Ch. 2.9 - Prob. 1E Ch. 2.9 - Prob. 2E Ch. 2.9 - Prob. 3E Ch. 2.9 - Prob. 4E Ch. 2.9 - Prob. 5E Ch. 2.9 - Prob. 6E Ch. 2.9 - Prob. 7E Ch. 2.9 - Prob. 8E Ch. 2.9 - Prob. 9E Ch. 2.9 - Prob. 10E Ch. 2.9 - Prob. 11E Ch. 2.9 - Prob. 12E Ch. 2.9 - Prob. 13E Ch. 2.9 - Prob. 14E Ch. 2.9 - Prob. 15E Ch. 2.9 - Prob. 16E Ch. 2.9 - Prob. 17E Ch. 2.9 - Prob. 18E Ch. 2.9 - Prob. 19E Ch. 2.9 - Prob. 20E Ch. 2.9 - Prob. 21E Ch. 2.9 - Prob. 22E Ch. 2.9 - Prob. 23E Ch. 2.9 - Prob. 24E Ch. 2.9 - Prob. 25E Ch. 2.9 - Prob. 26E Ch. 2.9 - Prob. 27E Ch. 2.9 - Prob. 28E Ch. 2.9 - Prob. 29E Ch. 2.9 - Prob. 30E Ch. 2.9 - Prob. 31E Ch. 2.9 - Prob. 32E Ch. 2.9 - Prob. 33E Ch. 2.9 - Prob. 34E Ch. 2.9 - Prob. 35E Ch. 2.9 - Prob. 36E Ch. 2.9 - Prob. 37E Ch. 2 - Prob. 1CRE Ch. 2 - Prob. 2CRE Ch. 2 - Prob. 3CRE Ch. 2 - Prob. 4CRE Ch. 2 - Prob. 5CRE Ch. 2 - Prob. 6CRE Ch. 2 - Prob. 7CRE Ch. 2 - Prob. 8CRE Ch. 2 - Prob. 9CRE Ch. 2 - Prob. 10CRE Ch. 2 - Prob. 11CRE Ch. 2 - Prob. 12CRE Ch. 2 - Prob. 13CRE Ch. 2 - Prob. 14CRE Ch. 2 - Prob. 15CRE Ch. 2 - Prob. 16CRE Ch. 2 - Prob. 17CRE Ch. 2 - Prob. 18CRE Ch. 2 - Prob. 19CRE Ch. 2 - Prob. 20CRE Ch. 2 - Prob. 21CRE Ch. 2 - Prob. 22CRE Ch. 2 - Prob. 23CRE Ch. 2 - Prob. 24CRE Ch. 2 - Prob. 25CRE Ch. 2 - Prob. 26CRE Ch. 2 - Prob. 27CRE Ch. 2 - Prob. 28CRE Ch. 2 - Prob. 29CRE Ch. 2 - Prob. 30CRE Ch. 2 - Prob. 31CRE Ch. 2 - Prob. 32CRE Ch. 2 - Prob. 33CRE Ch. 2 - Prob. 34CRE Ch. 2 - Prob. 35CRE Ch. 2 - Prob. 36CRE Ch. 2 - Prob. 37CRE Ch. 2 - Prob. 38CRE Ch. 2 - Prob. 39CRE Ch. 2 - Prob. 40CRE Ch. 2 - Prob. 41CRE Ch. 2 - Prob. 42CRE Ch. 2 - Prob. 43CRE Ch. 2 - Prob. 44CRE Ch. 2 - Prob. 45CRE Ch. 2 - Prob. 46CRE Ch. 2 - Prob. 47CRE Ch. 2 - Prob. 48CRE Ch. 2 - Prob. 49CRE Ch. 2 - Prob. 50CRE Ch. 2 - Prob. 51CRE Ch. 2 - Prob. 52CRE Ch. 2 - Prob. 53CRE Ch. 2 - Prob. 54CRE Ch. 2 - Prob. 55CRE Ch. 2 - Prob. 56CRE Ch. 2 - Prob. 57CRE Ch. 2 - Prob. 58CRE Ch. 2 - Prob. 59CRE Ch. 2 - Prob. 60CRE Ch. 2 - Prob. 61CRE Ch. 2 - Prob. 62CRE Ch. 2 - Prob. 63CRE Ch. 2 - Prob. 64CRE Ch. 2 - Prob. 65CRE Ch. 2 - Prob. 66CRE Ch. 2 - Prob. 67CRE Ch. 2 - Prob. 68CRE Ch. 2 - Prob. 69CRE Ch. 2 - Prob. 70CRE Ch. 2 - Prob. 71CRE Ch. 2 - Prob. 72CRE Ch. 2 - Prob. 73CRE Ch. 2 - Prob. 74CRE Ch. 2 - Prob. 75CRE Ch. 2 - Prob. 76CRE Ch. 2 - Prob. 77CRE Ch. 2 - Prob. 78CRE Ch. 2 - Prob. 79CRE Ch. 2 - Prob. 80CRE

Knowledge Booster

$Calculus$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.

An interval of length 0.025 containing the root of the given function found in the given interval by applying the Bisection method twice.

Solution Summary: The author explains the Bisection method, based on the intermediate value theorem for continuous functions.

Concept explainers

Videos

An interval of length 0.025 containing the root of the given function found in the given interval by applying the Bisection method twice.

Want to see the full answer?

Chapter 2 Solutions