Explanation Given data: Frequency is 870 KHz. Power is 50,000 W. Formula used: Rate of photon transmitted is given as follows. R = p h f (1) Here, h is the planks constant, which has a standard value as 6.63 × 10 − 34 J .s , p is the power, f is the frequency, and R is the rate of photon transmitted. Explanation: For wavelength of DVD player, Substitute 6.63 × 10 − 34 J ⋅ s for h , 50,000 W for p , and 870 KHz for f in equation (1), R = 50,000 W ( 6.63 × 10 − 34 J ⋅ s ) ( 870KHz ) = 50,000 W ( 6

College Physics: A Strategic Approach (3rd Edition)

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ISBN: 9780321902559

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Question

Chapter 28, Problem 23P

To determine

The number of photon emitted each second.

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Chapter 28, Problem 22P

Chapter 28, Problem 24P

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Concept Simulation 26.4 provides the option of exploring the ray diagram that applies to this problem. The distance between an object and its image formed by a diverging lens is 5.90 cm. The focal length of the lens is -2.60 cm. Find (a) the image distance and (b) the object distance.

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Chapter 28 Solutions

College Physics: A Strategic Approach (3rd Edition)

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