Explanation 1) Concept: We use the concept of conservation of mechanical energy and magnetic and centripetal force . We can rearrange the energy conservation equation for velocity. Also from the centripetal force and magnetic force equation, we can write the equation for velocity. Equating these two velocities’ equations and plugging the value of slope from the graph r V 1 2 , we can find the magnetic field. 2) Formulae: i) P . E i + K . E i = P . E f + K . E f ii) F B = q v B iii) F c p = m v 2 r 3) Given: i) Scale on y axis is r s = 3.0 m m ii) Scale on x axis is V s 1 2 = 40.0 V 1 2 iii) Figure 28-38 is the graph of radius vs. potential. 4) Calculations: P . E i + K . E i = P . E f + K . E f Here potential energy is the electrical potential energy. We can write q V i + 1 2 m v i 2 = q V f + 1 2 m v f 2 Initially kinetic energy is zero, and finally potential energy is zero. We can write q V i = 1 2 m v f 2 Rearranging it for velocity, we get v f = 2 q V i m … … … … … . . ( 1 ) The magnetic force provides the centripetal force, so we can write F c p = F B m v f 2 r = q v f B Rearranging for velocity, we get v f = q B r m … … … … ( 2 ) From equation (1) and (2), we can write q B r m = 2 q V i m 1 2 q B m r V i 1 2 = 2 q m 1 2 We can find the slope r V i 1 2 from the graph

11th Edition

ISBN: 9781119459170

Author: Halliday

Publisher: WILEY

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Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.

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Chapter 28, Problem 20P

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Magnitude of magnetic field.

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Chapter 28, Problem 19P

Chapter 28, Problem 21P

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Chapter 28 Solutions

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Ch. 28 - Prob. 1Q Ch. 28 - Prob. 2Q Ch. 28 - Prob. 3Q Ch. 28 - Prob. 4Q Ch. 28 - In Module 28-2, we discussed a charged particle...Ch. 28 - Prob. 6Q Ch. 28 - Figure 28-27 shows the path of an electron that...Ch. 28 - Figure 28-28 shows the path of an electron in a...Ch. 28 - Prob. 9Q Ch. 28 - Particle round about. Figure 28-29 shows 11 paths...

Ch. 28 - Prob. 11Q Ch. 28 - Prob. 12Q Ch. 28 - Prob. 1P Ch. 28 - A particle of mass 10 g and charge 80 C moves...Ch. 28 - An electron that has an instantaneous velocity of...Ch. 28 - An alpa particle travels at a velocity of...Ch. 28 - GO An electron moves through a unifrom magnetic...Ch. 28 - Prob. 6P Ch. 28 - Prob. 7P Ch. 28 - An electric field of 1.50 kV/m and a perpendicular...Ch. 28 - ILW In Fig. 28-32, an electron accelerated from...Ch. 28 - A proton travels through uniform magnetic and...Ch. 28 - Prob. 11P Ch. 28 - Go At time t1 an electron is sent along the...Ch. 28 - Prob. 13P Ch. 28 - A metal strip 6.50 cm long, 0.850 cm wide, and...Ch. 28 - Prob. 15P Ch. 28 - Prob. 16P Ch. 28 - An alpha particle can be produced in certain...Ch. 28 - Prob. 18P Ch. 28 - Prob. 19P Ch. 28 - Prob. 20P Ch. 28 - SSM An electron of kinetic energy 1.20 keV circles...Ch. 28 - In a nuclear experiment a proton with kinetic...Ch. 28 - What uniform magnetic field, applied perpendicular...Ch. 28 - An electron is accelerated from rest by a...Ch. 28 - a Find the frequency of revolution of an electron...Ch. 28 - Prob. 26P Ch. 28 - A mass spectrometer Fig. 28-12 is used to separate...Ch. 28 - A particle undergoes uniform circular motion of...Ch. 28 - An electron follows a helical path in a uniform...Ch. 28 - GO In Fig. 28-40. an electron with an initial...Ch. 28 - A particular type of fundamental particle decays...Ch. 28 - An source injects an electron of speed v = 1.5 ...Ch. 28 - Prob. 33P Ch. 28 - An electron follows a helical path in a uniform...Ch. 28 - A proton circulates in a cyclotron, beginning...Ch. 28 - Prob. 36P Ch. 28 - Prob. 37P Ch. 28 - In a certain cyclotron a proton moves in a circle...Ch. 28 - SSM A horizontal power line carries a current of...Ch. 28 - A wire 1.80 m long carries a current of 13.0 A and...Ch. 28 - Prob. 41P Ch. 28 - Prob. 42P Ch. 28 - A single-turn current loop, carrying a current of...Ch. 28 - Prob. 44P Ch. 28 - ACA /ACwire 50.0 cm long carries a 0.500 A current...Ch. 28 - In Fig. 28-44, a metal wire of mass m = 24.1 mg...Ch. 28 - GO A 1.0 kg copper rod rests on two horizontal...Ch. 28 - GO A long, rigid conductor, lying along an x axis,...Ch. 28 - Prob. 49P Ch. 28 - An electron moves in a circle of radius r = 5.29 ...Ch. 28 - Prob. 51P Ch. 28 - Prob. 52P Ch. 28 - Prob. 53P Ch. 28 - A magnetic dipole with a dipole moment of...Ch. 28 - Prob. 55P Ch. 28 - Prob. 56P Ch. 28 - Prob. 57P Ch. 28 - Prob. 58P Ch. 28 - A Current loop, carrying a current of 5.0 A, is in...Ch. 28 - Prob. 60P Ch. 28 - Prob. 61P Ch. 28 - Prob. 62P Ch. 28 - A circular loop of wire having a radius of 8.0 cm...Ch. 28 - GO Figure 28-52 gives the orientation energy U of...Ch. 28 - Prob. 65P Ch. 28 - Prob. 66P Ch. 28 - A stationary circular wall clock has a face with a...Ch. 28 - A wire lying along a y axis from y = 0 to y =...Ch. 28 - Atom 1 of mass 35 u and atom 2 of mass 37 u are...Ch. 28 - Prob. 70P Ch. 28 - Physicist S. A. Goudsmit devised a method for...Ch. 28 - A beam of electrons whose kinetic energy is K...Ch. 28 - Prob. 73P Ch. 28 - Prob. 74P Ch. 28 - Prob. 75P Ch. 28 - Prob. 76P Ch. 28 - Prob. 77P Ch. 28 - In Fig. 28-8, show that the ratio of the Hall...Ch. 28 - Prob. 79P Ch. 28 - An electron is moving at 7.20 106 m/s in a...Ch. 28 - Prob. 81P Ch. 28 - Prob. 82P Ch. 28 - Prob. 83P Ch. 28 - A write lying along an x axis from x = 0 to x =...Ch. 28 - Prob. 85P Ch. 28 - Prob. 86P Ch. 28 - Prob. 87P Ch. 28 - Prob. 88P Ch. 28 - In Fig. 28-58, an electron of mass m, charge e,...Ch. 28 - Prob. 90P Ch. 28 - Prob. 91P Ch. 28 - An electron that is moving through a uniform...

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Magnitude of magnetic field.

Solution Summary: The author explains the concept of conservation of mechanical energy and magnetic and centripetal force. Equating these two velocities’ equations and plugging the value of slope from the graph, they can find the magnetic field.

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To find: Magnitude of magnetic field.

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Chapter 28 Solutions

To find:

Magnitude of magnetic field.