Chapter 28, Problem 1PLA

To determine

The combination of the total resistance connected in series.

Answer to Problem 1PLA

Option (c) and (e) greater than $R_3$ and equal to $R_1+R_2+R_3$.

Explanation of Solution

Given, $R_1<R_2<R_3$ and they are connected in series.

Write the formula to find the total resistance of the circuit of resistors connected in series.

    $R_e=R_1+R_2+R_3+\mathrm{...}$

Here, $R_e$ is the equivalent resistance of the circuit and $R_1,R_2\&R_3$ is the individual resistance of the resistors.

Conclusion:

1. (a) The total resistance is the sum of the individual resistance. Therefore, it cannot be less than any individual resistance. Thus, option (a) is incorrect.
2. (b) The total resistance is the sum of the individual resistance. Therefore, it cannot be less than any individual resistance. Thus, option (b) is incorrect.
3. (c) The total resistance is the sum of the individual resistance. Therefore, it must be greater than $R_3$. Thus, option (c) is correct.
4. (d) Since, $R_1<R_2<R_3$, the value of $R_1\&R_2$ are less than $R_3$. Option (d) is incorrect.
5. (e) The total resistance is the sum of the individual resistance. Thus, option (e) is correct.