Explanation Given data: Wavelength1 is 437 nm. Wavelength2 is 533 nm. Wavelength3 is 564 nm Formula used: Consider the work function equation. E = h c λ (1) Here, h is the planks constant, which has a standard value as 6.63 × 10 − 34 J ⋅ s , c is the speed of light , which has a standard value as 3 × 10 8 m s , λ is the wavelength. Explanation: For wavelength 1, Substitute 6.63 × 10 − 34 J ⋅ s for h , 3 × 10 8 m s for c , and 437 nm for λ in equation (1), E = ( 6.63 × 10 − 34 J ⋅ s ) ( 3 × 10 8 m s ) 437 nm = ( 6.63 × 10 − 34 J ⋅ s ) ( 3 × 10 8 m s ) 437 × 10 − 9 m = 0.0455 × 10 − 17 J Consider conversion factor for J to eV. 1 J = 1 1.6 × 10 − 19 eV Convert the energy value to eV by using conversion factor. E = 0.0455 × 10 − 17 1.6 × 10 − 19 eV = 0 .0284 × 10 2 eV = 2.84 eV For wavelength 2, Substitute 6.63 × 10 − 34 J ⋅ s for h , 3 × 10 8 m s for c , and 533 nm for λ in equation (1), E = ( 6.63 × 10 − 34 J ⋅ s ) × ( 3 × 10 8 m s ) 533nm = ( 6

Mastering Physics with Pearson eText -- Standalone Access Card -- for College Physics: A Strategic Approach (3rd Edition)

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Chapter 28, Problem 19P

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The energy of photon at different wavelength.

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Chapter 28, Problem 18P

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The energy of photon at different wavelength.

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Chapter 28 Solutions