(a)
Interpretation:
Identify whether the given pair of monomers form chain-growth or step-growth
Concept introduction:
Polymers can be classified as chain-growth and step-growth polymers. Chain-growth polymers are the one which are formed when monomer is added to the other monomer growing chain one at a time. This growing polymer chain usually has only one reactive site. This site is called growth point. Step-growth polymers are the one when the monomers react with each other to form oligomers. These oligomers are joined together to form polymers. This usually occurs when bifunctional monomers are used. This has got two growth points.
To identify: whether the monomers used to form chain-growth or step-growth polymer.
(b)
Interpretation:
Identify whether the given pair of monomers form chain-growth or step-growth polymers.
Concept introduction:
Polymers can be classified as chain-growth and step-growth polymers. Chain-growth polymers are the one which are formed when monomer is added to the other monomer growing chain one at a time. This growing polymer chain usually has only one reactive site. This site is called growth point. Step-growth polymers are the one when the monomers react with each other to form oligomers. These oligomers are joined together to form polymers. This usually occurs when bifunctional monomers are used. This has got two growth points.
To identify: whether the monomers used to form chain-growth or step-growth polymer.
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Chapter 27 Solutions
ORGANIC CHEMISTRY (LL) >CUSTOM PACKAGE<
- What is the reaction mechanism for this?arrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. + Drawing Arrows CH3ONA, CH3OH heat : Br:O Na → H H Br Na + H H H H H :0: .H + Undo Reset Done Q CH3 Drag To Pan +arrow_forwardWhat is the reaction mechanism for this?arrow_forward
- 20.19 Predict the structure of the major 1,2-addition product formed by reaction of one mole of Cl₂ with 3-methylenecyclohexene. Also predict the structure of the 1,4-addition product formed under these conditions. 20.20 Which of the two molecules shown do you expect to be the major product formed by 1,2-addition of HCI to cyclopentadiene? Explain. Cyclopentadiene + HC 3-Chlorocyclopentene (racemic) or 4-Chlorocyclopentene (racemic)arrow_forward20.35 Propose structural formulas for compounds A and B and specify the configuration of compound B. EtO₂C 250°C C14H2004 CO₂Et 1. Oso, then NaHSO3 2. HIO4 C14H2006 A Barrow_forward20.21 Predict the major product formed by 1,4-addition of HCI to cyclopentadiene. 20.22 Draw structural formulas for the two constitutional isomers with the molecular for- mula C₂H,Br, formed by adding one mole of Br, to cyclopentadiene.arrow_forward
- Add substituents to draw the conformer below (sighting down the indicated bond), then rotate the back carbon to provide the conformation that will be capable of an E2 elimination. R/S stereochemistry is graded. + I I H CH3 Ph Досн Br OCH 3 Drawing Q H Atoms, Bonds and Rings Charges Tap a node to see suggestions. H H H H H Undo Reset Remove Done Rotatearrow_forward20.17 Predict the structure of the major product formed by 1,2-addition of HBr to 3-methylenecyclohexene. 3-Methylenecyclohexene 20.18 Predict the major product formed by 1,4-addition of HBr to 3-methylenecyclohexene.arrow_forward+ Draw a vicinal alkyl bromide that would produce the following alkene in an E2 elimination. Use a dash or wedge bond to indicate stereochemistry on asymmetric centers, where applicable. Ignore any inorganic byproducts. Br Drawing Strong Base H Q Atoms, Bonds Charges and Rings Draw or tap a new bond to see suggestions. Remove Done 語 Reset Undo + Drag To Panarrow_forward
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