(a) Explanation Given data: γ = 1.01 . Formula used: Write the expression for Kinetic energy ( K ) . K = ( γ − 1 ) m c 2 (1) Here, γ is the momentum factor, m is the mass, and c is the speed of light , which is known as 3.0 × 10 8 m s . Explanation: Refer to TABLE 20.1 in the text book for Protons and electrons. The mass of electron is 9.11 × 10 − 31 kg . Substitute 1.01 for γ , 9.11 × 10 − 31 kg for m and 3.0 × 10 8 m s for c in equation (1), K = ( 1.01 − 1 ) ( 9.11 × 10 − 31 kg ) ( 3.0 × 10 8 m s ) 2 = ( 0.01 ) ( 9.11 × 10 − 31 kg ) ( 9 b. To determine To find: The kinetic energy of an proton in MeV.

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ISBN: 9780134700427

Author: Knight

Publisher: PEARSON

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Relativistic Energy and Momentum

According to classical physics, time flow is the same for every observer. But according to einstein's theory, time flow is different for different observers. The idea that time flow is not the same for all may sound strange because we may not experience …

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Chapter 27, Problem 76GP

(a)

To determine

To find: The kinetic energy of an electron in MeV.

To determine

To find: The kinetic energy of an proton in MeV.

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Chapter 27, Problem 75GP

Chapter 27, Problem 77GP

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Chapter 27 Solutions

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The kinetic energy of an electron in MeV.

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To find: The kinetic energy of an electron in MeV.

To find: The kinetic energy of an proton in MeV.

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Chapter 27 Solutions