Chapter 27, Problem 52GP

(a)

To determine

The net area of earth exposed to sunlight, if the radius of earth is $6.38\times {10}^6\text{m}$.

(b)

To determine

The moment of the photons hitting earth’s surface each second, if the intensity of solar radiation is $1400\text{ J}\cdot {\text{s/m}}^2$. The radius of earth is $6.38\times {10}^6\text{m}$.

(c)

To determine

The average force of the radiation on earth’s surface using the impulse-momentum equation, if the intensity of solar radiation is $1400\text{ J}\cdot {\text{s/m}}^2$. The radius of earth is $6.38\times {10}^6\text{m}$.