The plates of an air-filled parallel-plate capacitor with a plate area of 16.0 cm2 and a separation of 9.00 mm are charged to a 145-V potential difference. After the plates are disconnected from the source, a porcelain dielectric with k =20 is inserted between the plates of the capacitor. a. What is the charge on the capacitor before and after the dielectric is inserted? b. What is the capacitance of the capacitor after the dielectric is inserted? c. What is the potential difference between the plates of the capacitor after the dielectric is inserted? d. What is the magnitude of the change in the energy stored in the capacitor after the dielectric is inserted?

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A: Given: Charge is 30 nC Radius is 30 cm or 0.3 m

Q: 1. Small charges q1 = + 7.5µC and q2 = - 2.5µC are brought in from infinity and fixed on the x axis…

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Q: 2. A capacitor consists of two 6.5- cm-diameter circular plates separated by 1.0 mm. The plates are…

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Q: 1. Small charges q1 = + 7.5µC and q 2 = - 2.5µC are brought in from infinity and fixed on the x axis…

A:

Q: A parallel-plate capacitor is made of two circular plates, each with a diameter of 2.50x10^-3 m. The…

A: Given that, The diameter of the circular plates, D = 2.50 x 10-3 m The separation between the…

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A: Disclaimer: “Since you have asked posted a question with multiple sub-parts, we will solve the first…

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A: Speed of proton = 200000 m/s Mass of proton = 1.67×10-27 kg Charge on proton= 1.6×10-19 C

Q: 5. A capacitor is charged by a battery. It may or may not have been removed from this battery. A…

A: Ques: A capacitor is charged by battery. Let charge on capacitor = Q capacitance = C

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.