EBK ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG
4th Edition
ISBN: 9781119659525
Author: Klein
Publisher: WILEY CONS
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Question
Chapter 27, Problem 41PP
(a)
Interpretation Introduction
Interpretation:
Syndiotactic poly (vinyl chloride) segments need to be drawn.
Concept introduction:
If the polymer formed has chiral centers then with the relative configuration of the chiral centers the
(b)
Interpretation Introduction
Interpretation:
Isotactic polystyrene segments need to be drawn.
Concept introduction:
If the polymer formed has chiral centers then with the relative configuration of the chiral centers the polymers can be classified as isotactic, Syndiotactic or atactic. When monosubstituted ethylenes are used as monomer the polymer formed has huge number of chiral centers. Isotactic means all the chiral center has the same configuration. Syndiotactic means the chiral centers has alternating configuration. Atactic means the chiral centers are in random arrangement.
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Please explain your steps and thought process. Thank you!
Using the general properties of equilibrium constants
At a certain temperature, the equilibrium constant K for the following reaction is 1.3 × 10 4:
Cl2(g) + CHCl3(g) HCl(g) + CC₁(g)
Use this information to complete the following table.
Suppose a 16. L reaction vessel is filled with 1.6 mol of HCI and
1.6 mol of CCl4. What can you say about the composition of the
mixture in the vessel at equilibrium?
There will be very little Cl2 and CHCl3.
☐ x10
There will be very little HCI and CCl4.
Neither of the above is true.
What is the equilibrium constant for the following reaction? Be
sure your answer has the correct number of significant digits.
HCl(g)+CC14(g)
12
Cl2(9)+CHCl3(9)
K = 0 ☐
What is the equilibrium constant for the following reaction? Be
sure your answer has the correct number of significant digits.
2 Cl₂(9)+2CHCl3(9)
2 HCl(9)+2CC₁₁(9)
K =
✓
00.
18
Ar
Chapter 27 Solutions
EBK ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG
Ch. 27.2 - Prob. 1CCCh. 27.2 - Prob. 2CCCh. 27.3 - Prob. 3CCCh. 27.3 - Prob. 4CCCh. 27.3 - Prob. 5CCCh. 27.4 - Prob. 1LTSCh. 27.4 - Prob. 6PTSCh. 27.4 - Prob. 11CCCh. 27.4 - Prob. 12CCCh. 27.4 - Prob. 2LTS
Ch. 27.4 - Prob. 13PTSCh. 27.4 - Prob. 14PTSCh. 27.5 - Prob. 17CCCh. 27.5 - Prob. 18CCCh. 27.6 - Prob. 19CCCh. 27.6 - Prob. 20CCCh. 27.8 - Prob. 21CCCh. 27 - Prob. 22PPCh. 27 - Prob. 23PPCh. 27 - Prob. 24PPCh. 27 - Prob. 25PPCh. 27 - Prob. 26PPCh. 27 - Prob. 27PPCh. 27 - Prob. 28PPCh. 27 - Prob. 29PPCh. 27 - Prob. 30PPCh. 27 - Prob. 31PPCh. 27 - Prob. 32PPCh. 27 - Prob. 33PPCh. 27 - Prob. 34PPCh. 27 - Prob. 35PPCh. 27 - Prob. 36PPCh. 27 - Prob. 37PPCh. 27 - Prob. 38PPCh. 27 - Prob. 39PPCh. 27 - Prob. 40PPCh. 27 - Prob. 41PPCh. 27 - Prob. 42PP
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