Explanation Given: I is the 8.0 A l is 20 m ρ of copper is 1.7 ( 10 − 8 ) Ωm Diameter d is 2 mm Formula Used: The formula used is given by: V = I R Where V is the voltage R is the resistance I is the current And the resistance is given by R = ρ l A Where ρ is the resistivity l is the length of the current carrying conductor. A is the cross section of the current carrying conductor. Calculation: The area of cross section of the wire can be calculated from the diameter using the formula: A = π 4 d 2 A wire of diameter d of value 2 mm has a cross section of A = π 4 ( 2 ( 10 − 3 ) ) 2 A wire of diameter d of value 2 mm has a cross section of 3

Student Workbook for Physics for Scientists and Engineers: A Strategic Approach, Vol 1. (Chs 1-21)

4th Edition

ISBN: 9780134110646

Author: Randall D. Knight (Professor Emeritus)

Publisher: PEARSON

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Question

Chapter 27, Problem 37EAP

To determine

The potential difference in the wire.

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Chapter 27 Solutions

Student Workbook for Physics for Scientists and Engineers: A Strategic Approach, Vol 1. (Chs 1-21)

Ch. 27 - Prob. 1CQ Ch. 27 - Prob. 2CQ Ch. 27 - The electron drift speed in a wire is exceedingly...Ch. 27 - Prob. 4CQ Ch. 27 - Prob. 5CQ Ch. 27 - All the wires in FIGURE Q27.6 are made of the same...Ch. 27 - Both batteries in FIGURE Q27.7 are ideal and...Ch. 27 - Both batteries in FIGURE Q27.8 are ideal and...Ch. 27 - The wire in FIGURE Q27.9 consists of two segments...Ch. 27 - Prob. 10CQ

Ch. 27 - ll. The wires in FIGURE Q27.11 are all made of the...Ch. 27 - Which, if any, of these statements are true? (More...Ch. 27 - Prob. 1EAP Ch. 27 - Prob. 2EAP Ch. 27 - .0 × 1016 electrons flow through a cross section...Ch. 27 - Prob. 4EAP Ch. 27 - Prob. 5EAP Ch. 27 - Prob. 6EAP Ch. 27 - Prob. 7EAP Ch. 27 - Prob. 8EAP Ch. 27 - Prob. 9EAP Ch. 27 - Prob. 10EAP Ch. 27 - Prob. 11EAP Ch. 27 - The current in an electric hair dryer is 10.0 A....Ch. 27 - 13. When a nerve cell fires, charge is...Ch. 27 - Prob. 14EAP Ch. 27 - Prob. 15EAP Ch. 27 - Prob. 16EAP Ch. 27 - Prob. 17EAP Ch. 27 - Prob. 18EAP Ch. 27 - Prob. 19EAP Ch. 27 - Prob. 20EAP Ch. 27 - Prob. 21EAP Ch. 27 - Prob. 22EAP Ch. 27 - Prob. 23EAP Ch. 27 - 24. The two segments of the wire in FIGURE EX27.24...Ch. 27 - A 1.5 V battery provides 0.50 A of current. a. At...Ch. 27 - Prob. 26EAP Ch. 27 - Prob. 27EAP Ch. 27 - Prob. 28EAP Ch. 27 - Prob. 29EAP Ch. 27 - Prob. 30EAP Ch. 27 - Prob. 31EAP Ch. 27 - Prob. 32EAP Ch. 27 - Prob. 33EAP Ch. 27 - Prob. 34EAP Ch. 27 - Prob. 35EAP Ch. 27 - Prob. 36EAP Ch. 27 - Prob. 37EAP Ch. 27 - Prob. 38EAP Ch. 27 - Prob. 39EAP Ch. 27 - Prob. 40EAP Ch. 27 - Prob. 41EAP Ch. 27 - Prob. 42EAP Ch. 27 - Prob. 43EAP Ch. 27 - Prob. 44EAP Ch. 27 - Prob. 45EAP Ch. 27 - Prob. 46EAP Ch. 27 - Prob. 47EAP Ch. 27 - Prob. 48EAP Ch. 27 - Prob. 49EAP Ch. 27 - Variations in the resistivity of blood can give...Ch. 27 - The conducting path between the right hand and the...Ch. 27 - The conductive tissues of the upper leg can be...Ch. 27 - The resistivity of a metal increases slightly with...Ch. 27 - Prob. 54EAP Ch. 27 - You need to design a 1.0 A fuse that “blows” if...Ch. 27 - I A hollow metal cylinder has inner radius a....Ch. 27 - A hollow metal sphere has inner radius a, outer...Ch. 27 - The total amount of charge in coulombs that has...Ch. 27 - The total amount of charge that has entered a wire...Ch. 27 - The current in a wire at time t is given by the...Ch. 27 - The current supplied by a battery slowly decreases...Ch. 27 - The two wires in FIGURE P27.62 are made of the...Ch. 27 - What diameter should the nichrome wire in FIGURE...Ch. 27 - An aluminum wire consists of the three segments...Ch. 27 - A wire of radius R has a current density that...Ch. 27 - A 0.60 -mm-diameter wire made from an alloy (a...Ch. 27 - A 20 -cm-long hollow nichrome tube of inner...Ch. 27 - Prob. 68EAP Ch. 27 - Prob. 69EAP Ch. 27 - Prob. 70EAP Ch. 27 - Prob. 71EAP Ch. 27 - Prob. 72EAP Ch. 27 - Prob. 73EAP Ch. 27 - Prob. 74EAP Ch. 27 - Prob. 75EAP Ch. 27 - Prob. 76EAP

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