Explanation Given info: The length of wire at which gold can be drawn is 2.40 km . The density of gold is 19.3 × 10 3 kg/m 3 and its resistivity is 2.44 × 10 − 8 Ω ⋅ m . Write the expression for volume of the gold. V = m ρ Here, V is the volume of the gold. m is the mass of the gold. ρ is the density of gold. Substitute 1 g for m and 19.3 × 10 3 kg/m 3 for ρ in above equation. V = ( 1 g ) ( 1 × 10 − 3 kg 1 g ) 19.3 × 10 3 kg/m 3 = 10 − 3 kg 19.3 × 10 3 kg/m 3 = 0.0518 × 10 − 6 m 3 ≈ 5.2 × 10 − 8 m 3 Write the expression for the cross sectional area of the metal. A = V l Here, A is the area of the metal. l is the length of wire. Substitute 5.2 × 10 − 8 m 3 for V and 2.40 km for l in above equation. A = 5.2 × 10 − 8 m 3 ( 2.40 km ) ( 1 × 10 3 m 1 km ) = 5

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ISBN: 8220100454899

Author: Jewett

Publisher: Cengage Learning US

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Resistivity

Resistivity is a characteristic property of the conductor’s material that measures the extent to which the material opposes the flow of current. It is denoted by the Greek letter “rho”. Electrical resistivity, also known as specific resistance, depends o…

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Chapter 27, Problem 27.79AP

To determine

The resistance of wire at 20.0 °C .

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The resistance of wire at 20.0 ° C .

Solution Summary: The author analyzes the resistance of wire at 20.0° C and the density of gold.

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The resistance of wire at 20.0 °C .

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Chapter 27 Solutions