
Concept explainers
(a)
The amount of iron in 1.00 mole
of iron.
(a)

Answer to Problem 27.24P
Explanation of Solution
Given Info: The cross-sectional area of iron wire is
Explanation:
Amount of iron in one mole is given as,
It is the standard value for iron wire.
Convert the amount of iron into
Thus,
Conclusion:
Therefore,
(b)
The molar density of iron.
(b)

Answer to Problem 27.24P
Explanation of Solution
Given Info: The cross-sectional area of iron wire is
Explanation:
The formula for the molar density is,
Here,
Substitute
Thus, the molar density of iron is
Conclusion:
Therefore, the molar density of iron is
(c)
The number density of iron atoms.
(c)

Answer to Problem 27.24P
Explanation of Solution
Given Info: The cross-sectional area of iron wire is
Explanation:
The formula for the number density is,
Here,
Substitute
Thus, the number density of iron atoms is
Conclusion:
Therefore, the number density of iron atoms is
(d)
The number density of two conduction iron atoms.
(d)

Answer to Problem 27.24P
Explanation of Solution
Given Info: The cross-sectional area of iron wire is
Explanation:
The formula for the number density of two conduction atoms is,
Here,
Substitute
Thus, the number density of two conduction iron atoms is
Conclusion:
Therefore, the number density of two conduction iron atoms is
(e)
The drift speed of the conduction electrons.
(e)

Answer to Problem 27.24P
Explanation of Solution
Given Info: The cross-sectional area of iron wire is
Explanation:
Formula to calculate the drift speed is,
Substitute
Conclusion:
Therefore, the total drift speed of the conduction electrons is.
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Chapter 27 Solutions
Bundle: Physics for Scientists and Engineers, Technology Update, 9th Loose-leaf Version + WebAssign Printed Access Card, Multi-Term
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