Explanation Given: Wavelength range of visible spectrum, λ = 400 nm ∼ 750 nm Formula used: Energy is given by the formula E = h c λ Here, h = 6.62 × 10 − 34 J-s is Planck’s constant λ is the wavelength c = 3 × 10 8 m/s is the speed of light Calculation: The maximum energy in visible spectrum is calculated as E max = 6.62 × 10 − 34 × 3 × 10 8 400 × 10 − 9 = 4.9 × 10 − 19 J The minimum energy in visible spectrum is calculated as E min = 6.62 × 10 − 34 × 3 × 10 8 750 × 10 − 9 = 2...

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ISBN: 2818440037979

Author: GIANCOLI

Publisher: PEARSON

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Chapter 27, Problem 11P

To determine

Energy range of photon in visible spectrum in $J$ and in $eV$

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Chapter 27, Problem 10P

Chapter 27, Problem 12P

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Set ба ||Axl 49.32 6b 71 Ay 22 Magnitude of A Angle of A 24.04 Angle of -A 22 54 155.96 ° (pos Ax) 204.04 ° (neg Ax) 335.96 ° (pos Ax) ° (neg Ax) 115.77 ° (pos Ax) 295.77 ° (pos Ax) -39 81 208.78 ° (neg Ax) 28.78 ° (neg Ax)

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Chapter 27 Solutions

PHYSICS:PRINCIPLES W/ APPLICATIONS

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