EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 9780100793439
Author: KALPAKJIAN
Publisher: YUZU
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Chapter 27, Problem 10RQ
What is the difference between photochemical blanking and chemical blanking?
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Hello I was going over the solution for this probem and I'm a bit confused on the last part. Can you please explain to me 1^4 was used for the Co of the tubular cross section? Thank you!
Chapter 27 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 27 - Describe the similarities and differences between...Ch. 27 - Name the processes involved in chemical machining....Ch. 27 - Explain the difference between chemical machining...Ch. 27 - What is the underlying principle of...Ch. 27 - Explain how the EDM process is capable of...Ch. 27 - What are the important features of the Blue Arc...Ch. 27 - What are the capabilities of wire EDM? Could this...Ch. 27 - Explain why laser Microjet has a large depth of...Ch. 27 - Describe the advantages of water-jet machining.Ch. 27 - What is the difference between photochemical...
Ch. 27 - What type of workpiece is not suitable for...Ch. 27 - What is an undercut? Why must it be considered in...Ch. 27 - Explain the principle of hybrid machining.Ch. 27 - Give technical and economic reasons that the...Ch. 27 - Why is the preshaping or premachining of parts...Ch. 27 - Explain why the mechanical properties of workpiece...Ch. 27 - Prob. 17QLPCh. 27 - Prob. 18QLPCh. 27 - Why has electrical-discharge machining become so...Ch. 27 - Prob. 20QLPCh. 27 - Which of the advanced machining processes would...Ch. 27 - Which of the processes described in require a...Ch. 27 - Describe your thoughts regarding the laser-beam...Ch. 27 - Are deburring operations still necessary for some...Ch. 27 - List and explain factors that contribute to a poor...Ch. 27 - What is the purpose of the abrasives in...Ch. 27 - Which of the processes described in this chapter...Ch. 27 - Is kerf width important in wire EDM? Explain.Ch. 27 - Comment on your observations regarding Fig. 27.4.Ch. 27 - Why may different advanced machining processes...Ch. 27 - A 200-mm-deep hole that is 30 mm in diameter is...Ch. 27 - If the operation in Problem 27.31 were performed...Ch. 27 - A cutting-off operation is being performed with a...Ch. 27 - A 0.80-in.-thick copper plate is being machined by...Ch. 27 - Explain why it is difficult to produce sharp...Ch. 27 - Make a list of the processes described in this...Ch. 27 - Would the processes described in this chapter be...Ch. 27 - Prob. 38SDPCh. 27 - Describe your thoughts as to whether the...Ch. 27 - Make a list of machining processes that may be...Ch. 27 - At what stage is the abrasive in abrasive...Ch. 27 - Describe the similarities and differences among...Ch. 27 - Describe the similarities and differences among...Ch. 27 - Describe any workpiece size limitations in...Ch. 27 - Suggest several design applications for the types...Ch. 27 - Based on the topics covered in Parts III and IV,...Ch. 27 - Review Example 27.1 and explain the relevant...Ch. 27 - Precision engineering is a term that is used to...Ch. 27 - With appropriate sketches, describe the principles...Ch. 27 - Make a table of the process capabilities of the...Ch. 27 - One of the general concerns regarding advanced...Ch. 27 - It can be seen that several of the processes...
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- (Read image) (Answer given)arrow_forwardProblem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/sarrow_forwardProblem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4arrow_forward
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