PRESCOTT'S MICROBILOGY
11th Edition
ISBN: 9781264075515
Author: WILLEY
Publisher: MCG
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Chapter 26.8, Problem 1CC
Summary Introduction
Hepatitis B virus or HBV is the causative agent of the Hepatitis B. It is a potentially life-threatening disease that affects the liver. It is one of the important global health problems. This infection results in chronic infection and the infected people are prone to the risk of death due to liver cancer as well as cirrhosis.
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Chapter 26 Solutions
PRESCOTT'S MICROBILOGY
Ch. 26.1 - List some characteristics used in classifying...Ch. 26.1 - Prob. 2CCCh. 26.2 - Prob. 1MICh. 26.2 - Why do you think T4 evolved to initiate DNA...Ch. 26.2 - What function does HMC glycosylation serve?Ch. 26.2 - Explain why the T4 genome is circularly permuted.Ch. 26.2 - Prob. 1.2CCCh. 26.2 - How is a prophage induced to become active again?Ch. 26.2 - Describe the roles of cII, CIII, repressor (CI),...Ch. 26.2 - How do the temperate phages Mu and P1 differ from...
Ch. 26.2 - How is the envelope of this virus formed? How does...Ch. 26.2 - Why do cold sores recur throughout the lifetime of...Ch. 26.2 - In what part of the host cell does a herpesvirus...Ch. 26.2 - Many small DNA viruses rely on host enzymes for...Ch. 26.3 - Why is the X174 genome considered plus stranded?Ch. 26.3 - Why is it necessary for some ssDNA viruses to...Ch. 26.3 - Prob. 2CCCh. 26.3 - How do parvoviruses trick the host DNA polymerase...Ch. 26.4 - The rotavirus genome encodes 12 proteins. Suggest...Ch. 26.4 - Describe the life cycle of 6 phage. What makes...Ch. 26.4 - Prob. 3CCCh. 26.4 - In what ways are the life cycles of 6 and...Ch. 26.5 - Where in the host does the plus-strand RNA genome...Ch. 26.5 - How do some plus-strand viruses use polyproteins...Ch. 26.5 - What is an IRES? Why is it important?Ch. 26.5 - Prob. 3CCCh. 26.6 - How does that use of a segmented genome by...Ch. 26.6 - Prob. 2CCCh. 26.7 - Prob. 1MICh. 26.7 - Prob. 1CCCh. 26.7 - Prob. 2CCCh. 26.7 - Prob. 3CCCh. 26.8 - Prob. 1CCCh. 26.8 - Trace the HBV multiplication cycle, paying...Ch. 26 - Prob. 1RCCh. 26 - Prob. 2RCCh. 26 - Prob. 3RCCh. 26 - Prob. 4RCCh. 26 - No temperate RNA phages have yet been discovered....Ch. 26 - The choice between lysogeny and lysis is...Ch. 26 - Prob. 3ALCh. 26 - You are studying RNA viruses and have discovered a...Ch. 26 - Prob. 5ALCh. 26 - Prob. 6AL
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- With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forward
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