Explanation The initial conditions on voltage across a capacitor with capacitance C is V C ( 0.0 ) = 0 and the charge is i = 0.25 μ A with time t = 3.0 μ s . Rewrite the charge i = 0.25 μ A and the point t = 3.0 μ s as follows. i = 0.25 μ A = 0.25 × 10 − 6 A ( ∵ 1 μ A = 10 − 6 ) t = 3.0 μ s = 3.0 × 10 − 6 s ( ∵ 1 μ s = 10 − 6 ) Note that, the voltage across a capacitor with capacitance C is given by V C = 1 C ∫ i d t , where V C is measured in volts, C in farads, i in amperes, and t in seconds. Substitute i = 0.25 × 10 − 6 A and C = 0.10 × 10 − 6 F in V C = 1 C ∫ i d t and simplify for V C . V C = 1 0.10 × 10 − 6 ∫ ( 0.25 × 10 − 6 ) d t = 1 0.10 × 10 − 6 ( 0.25 × 10 − 6 ) t + C 1 Apply the initial condition on voltage across a capacitor with capacitance C to obtain C 1 as follows

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Chapter 26.1, Problem 22E

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The voltage after being charged by 0.25 μA for the time 3.0 μs.

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Chapter 26.1, Problem 21E

Chapter 26.1, Problem 23E

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Chapter 26 Solutions

Basic Technical Mathematics

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The voltage after being charged by 0.25 μ A for the time 3.0 μ s .

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The voltage after being charged by 0.25 μA for the time 3.0 μs.

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Chapter 26 Solutions