Explanation Given info: The object distance is 24 cm , the refractive index of red light is 1.572 , the refractive index of violet light is 1.605 and image distance of red light is 55.00 cm The focal length is inversely proportional to the term ( n − 1 ) f ∝ 1 n − 1 Here, n is the refractive index. The formula to calculate the focal length of red light is, f r = 1 n r − 1 Here, n r is the refractive index of red light. The formula to calculate the focal length of red light is, 1 f r = 1 v r − 1 u Here, u is the object distance. v r is the image distance of red light. Substitute 1 n r − 1 for f r in the above formula. 1 f r = 1 v r − 1 u 1 n r − 1 = 1 v r − 1 u (1) The formula to calculate the focal length of violet light is, f v = 1 n v − 1 Here, n v is the refractive index of violet light. The formula to calculate the focal length of violet light is, 1 f v = 1 v v − 1 u Here, u is the object distance. v v is the image distance of violet light. Substitute 1 n v − 1 for f v in the above formula. 1 f v = 1 v v − 1 u 1 n v − 1 = 1 v v − 1 u (2) Divide equation (1) and (2)

5th Edition

ISBN: 9780134051796

Author: Walker

Publisher: YUZU

See similar textbooks

Concept explainers

Refraction of Light

Refraction is a change in the direction of light rays when they travel from one medium to another. It is the bending of light when it goes through different media.

Angle of Refraction

Light is considered by many scientists to have dual nature, both particle nature and wave nature. First, Particle nature is one in which we consider a stream of packets of energy called photons. Second, Wave nature is considering light as electromagnetic…

Index of Refraction of Diamond

Diamond, the world’s hardest naturally occurring material and mineral known, is a solid form of the element carbon. The atoms are arranged in a crystal structure called diamond cubic. They exist in a huge variety of colours. Also, they are one of the bes…

Videos

Question

Chapter 26, Problem 86PCE

To determine

The image distance of violet light.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 26, Problem 85PCE

Chapter 26, Problem 87GP

Students have asked these similar questions

SARET CRKS AUTOWAY 12. A stone is dropped from the top of a cliff. It is seen to hit the ground below after 3.55 s. How high is the cliff? 13. A ball is dropped from rest at the top of a building that is 320 m tall. Assuming no air resistance, what is the speed of the ball just before it strikes the ground? 14. Estimate (a) how long it took King Kong to fall straight down from the top of the Empire State Building (280m high), and (b) his velocity just before "landing". Useful equations For Constant Velocity: V => D X = V₁t + Xo For Constant Acceleration: Vr = V + at X = Xo+Vot + v=V+2a(X-Xo) \prom = V +V V velocity t = time D Distance X = Final Position Xo Initial Position V = Final Velocity Vo Initial Velocity a = acceleration For free fall Yf = Final Position Yo Initial Position g = 9.80 m $2 For free fall: V = V + gt Y=Yo+Vo t + +gt V,² = V₁²+2g (Y-Yo) V+Vo Vprom= 2 6

Solve the problems

A 11 kg weight is attached to a spring with constant k = 99 N/m and subjected to an external force F(t) =-704 sin(5t). The weight is initially displaced 4 meters above equilibrium and given an upward velocity of 5 m/s. Find its displacement for t> 0. y(t) ון

Chapter 26 Solutions

EBK PHYSICS

Ch. 26.1 - A ray of light reflects from a horizontal flat...Ch. 26.2 - A meterstick is placed 40 cm in front of a plane...Ch. 26.3 - Rank the following spherical mirrors in order of...Ch. 26.4 - A spherical mirror with an object at the distance...Ch. 26.5 - (a) As a beam of light passes from flint glass to...Ch. 26.6 - The lenses shown in Figure 26-49 have objects that...Ch. 26.7 - An object at the distance do = 15 cm from a lens...Ch. 26.8 - Referring to Figure 26-53, do you expect the index...Ch. 26 - Two plane mirrors meet at right angles at the...Ch. 26 - Two plane mirrors meet at right angles at the...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The image distance of violet light.

Solution Summary: The author explains that the image distance of violet light is 47.3cm. The focal length is inversely proportional to the term (n-1).

Concept explainers

Videos

The image distance of violet light.

Want to see the full answer?

Chapter 26 Solutions