Conceptual Physics / MasteringPhysics (Book & Access Card)
Conceptual Physics / MasteringPhysics (Book & Access Card)
12th Edition
ISBN: 9780321908605
Author: Paul G. Hewitt
Publisher: PEARSON
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Chapter 26, Problem 80RCQ
To determine

Can we see and hear the radio waves.

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1.) Two long parallel current-carrying wires P and Q are separated by 0.10 m. The current in wire P is 5.0 A. The magnetic force on a length of 0.50 m of wire P due to the current in wire Q is 2.0 × 10-s N. (a) State and explain the magnitude of the force on a length of 0.50 m of wire Q due to the current in P. [2] (b) Calculate the current in wire Q. [2] (c) Another current-carrying wire R is placed parallel to wires P and Q and halfway between them as shown. wire P wire R wire Q 0.05 m 0.05 m The net magnetic force on wire Q is now zero. (c.i) State the direction of the current in R, relative to the current in P.[1] (c.ii) Deduce the current in R. [2]
2.) A 50.0 resistor is connected to a cell of emf 3.00 V. The voltmeter and the ammeter in the circuit are ideal. V A 50.00 (a) The current in the ammeter is 59.0 mA. Calculate the internal resistance of the cell. The circuit is changed by connecting another resistor R in parallel to the 50.0 resistor. V A 50.00 R (b) Explain the effect of this change on R is made of a resistive wire of uniform cross-sectional area 3.1 × 10-8 m², resistivity 4.9 × 10-70m and length L. The resistance of R is given by the equation R = KL where k is a constant. (b.i) the reading of the ammeter. [2] (b.ii) the reading of the voltmeter. [2] (c) Calculate k. State an appropriate unit for your answer. [3] [2]
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Chapter 26 Solutions

Conceptual Physics / MasteringPhysics (Book & Access Card)

Ch. 26 - Prob. 11RCQCh. 26 - Prob. 12RCQCh. 26 - Prob. 13RCQCh. 26 - Prob. 14RCQCh. 26 - Prob. 15RCQCh. 26 - Prob. 16RCQCh. 26 - Prob. 17RCQCh. 26 - Prob. 18RCQCh. 26 - Prob. 19RCQCh. 26 - Prob. 20RCQCh. 26 - Prob. 21RCQCh. 26 - Prob. 22RCQCh. 26 - Prob. 23RCQCh. 26 - Prob. 24RCQCh. 26 - Prob. 25RCQCh. 26 - Prob. 26RCQCh. 26 - Prob. 27RCQCh. 26 - Prob. 28RCQCh. 26 - Prob. 29RCQCh. 26 - Prob. 30RCQCh. 26 - Prob. 31RCQCh. 26 - Prob. 32RCQCh. 26 - Prob. 33RCQCh. 26 - Prob. 34RCQCh. 26 - Prob. 35RCQCh. 26 - Prob. 36RCQCh. 26 - Prob. 37RCQCh. 26 - Prob. 38RCQCh. 26 - Prob. 39RCQCh. 26 - Prob. 40RCQCh. 26 - Prob. 41RCQCh. 26 - Prob. 42RCQCh. 26 - Prob. 43RCQCh. 26 - Prob. 44RCQCh. 26 - Prob. 45RCQCh. 26 - Prob. 46RCQCh. 26 - Prob. 47RCQCh. 26 - Prob. 48RCQCh. 26 - Prob. 49RCQCh. 26 - Prob. 50RCQCh. 26 - Prob. 51RCQCh. 26 - Prob. 52RCQCh. 26 - Prob. 53RCQCh. 26 - Prob. 54RCQCh. 26 - Prob. 55RCQCh. 26 - Prob. 56RCQCh. 26 - Prob. 57RCQCh. 26 - Prob. 58RCQCh. 26 - Prob. 59RCQCh. 26 - Prob. 60RCQCh. 26 - Prob. 61RCQCh. 26 - Prob. 62RCQCh. 26 - Prob. 63RCQCh. 26 - Prob. 64RCQCh. 26 - Prob. 65RCQCh. 26 - Prob. 66RCQCh. 26 - Prob. 67RCQCh. 26 - 68. Why do objects illuminated by moonlight lack...Ch. 26 - Prob. 69RCQCh. 26 - Prob. 70RCQCh. 26 - Prob. 71RCQCh. 26 - Prob. 72RCQCh. 26 - Prob. 73RCQCh. 26 - Prob. 74RCQCh. 26 - Prob. 75RCQCh. 26 - Prob. 76RCQCh. 26 - Prob. 77RCQCh. 26 - We hear people talk of “ultraviolet light” and...Ch. 26 - Prob. 79RCQCh. 26 - Prob. 80RCQCh. 26 - Prob. 81RCQCh. 26 - Prob. 82RCQCh. 26 - Prob. 83RCQCh. 26 - Prob. 84RCQCh. 26 - Prob. 85RCQCh. 26 - Prob. 86RCQCh. 26 - Prob. 87RCQCh. 26 - Prob. 88RCQCh. 26 - Prob. 89RCQCh. 26 - Prob. 90RCQCh. 26 - Prob. 91RCQCh. 26 - Prob. 92RCQCh. 26 - Prob. 93RCQCh. 26 - Prob. 94RCQ
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